The Mole in Cambridge IGCSE Coordinated Science (0654): Molar Mass, Avogadro's Constant and Calculation Methods Explained
Who this is for: Cambridge IGCSE Coordinated Science (0654) students who want the mole — linking mass, particles and chemical amounts — to become a reliable source of marks instead of a formula-memorising exercise.
What query it owns: how to understand and revise the mole in Cambridge IGCSE Coordinated Science.
Why this is safe: this page owns the the-mole revision-guide angle, while Tutopiya’s The Mole subtopic page owns the learning resource and the free The Mole quiz owns the practice.
The mole is the chemist’s counting unit. Cambridge IGCSE Coordinated Science (0654) expects you to convert between mass, moles and number of particles, use relative atomic and formula masses, and apply mole ratios in simple stoichiometry. This guide links each idea to what examiners reward, so you can tackle calculation and definition questions with confidence.
Key takeaways
- One mole contains 6.02 × 10²³ particles (Avogadro’s constant).
- Relative atomic mass (Aᵣ) has no units; molar mass is in g/mol.
- Moles = mass ÷ molar mass (n = m/M).
- Number of particles = moles × 6.02 × 10²³.
- Mole ratios from balanced equations link amounts of reactants and products.
What is the mole in Cambridge IGCSE Coordinated Science?
The mole lets you count particles by weighing. Because atoms are too small to count individually, chemists use a standard amount — one mole — equal to Avogadro’s number of particles. The molar mass of a substance (in g/mol) numerically equals its relative formula mass, so a weighed sample tells you how many moles you have.
You can read the full explanation, worked examples and notes on Tutopiya’s The Mole subtopic page before you attempt questions.
Core formulas and relationships
| Quantity | Formula | Units |
|---|---|---|
| Moles from mass | n = m / M | mol = g ÷ (g/mol) |
| Mass from moles | m = n × M | g = mol × (g/mol) |
| Particles from moles | N = n × 6.02 × 10²³ | particles |
| Molar mass | Sum of Aᵣ values in formula | g/mol |
Relative mass — what examiners expect
| Term | Meaning | Example |
|---|---|---|
| Relative atomic mass (Aᵣ) | Average mass of an atom relative to ¹⁄₁₂ of carbon-12 | Aᵣ(C) = 12 |
| Relative formula mass (Mᵣ) | Sum of Aᵣ values in a formula | Mᵣ(H₂O) = 18 |
| Molar mass | Mass of one mole | H₂O = 18 g/mol |
The mole in past-paper wording: command words that matter
| Command word / phrase | What the question wants | Typical mole stem |
|---|---|---|
| Calculate | Use n = m/M or mole ratios | ”Calculate the number of moles in 8 g of oxygen gas.” |
| State | Short definition or value | ”State the value of Avogadro’s constant.” |
| Deduce | Work out from given data | ”Deduce the mass of 0.5 mol of CO₂.” |
| Use mole ratio | Apply balanced equation | ”How many moles of H₂O form from 2 mol of H₂?” |
Worked exam-style stems (how to answer the wording)
- “Calculate the number of moles in 9 g of water (Mᵣ = 18).” n = m/M = 9/18 = 0.5 mol. Mark-scheme reward: correct substitution and answer with unit.
- “State the number of particles in 1 mol of any substance.” 6.02 × 10²³ particles. Reward: correct value and idea of particles.
- “From the equation 2H₂ + O₂ → 2H₂O, how many moles of water form from 3 mol of hydrogen?” Mole ratio H₂:H₂O = 2:2 = 1:1, so 3 mol of water. Reward: correct ratio applied.
Test yourself with the The Mole quiz once you can convert between mass, moles and particles without a formula sheet.
How the mole connects to the rest of Coordinated Science chemistry
The mole underpins stoichiometry — reacting masses, limiting reagents and percentage yield. It builds on atomic structure and formula writing. The Cambridge IGCSE Coordinated Science resource hub links every Stoichiometry subtopic.
Common mistakes students make
- Confusing relative formula mass (no unit) with molar mass (g/mol).
- Using molecular mass for ionic compounds (use formula mass).
- Forgetting to convert mass to grams before dividing by molar mass.
- Mixing up mole ratio with mass ratio in equations.
- Rounding 6.02 × 10²³ incorrectly in multi-step calculations.
When you need more support
If mole calculations keep costing marks, work through the The Mole quiz, then get focused help from a Cambridge IGCSE Coordinated Science tutor.
Frequently asked questions
Is the mole hard in Coordinated Science? The concepts are straightforward once you practise n = m/M and mole ratios from balanced equations.
What is Avogadro’s constant? The number of particles in one mole: 6.02 × 10²³ mol⁻¹.
How do I find molar mass? Add the relative atomic masses of all atoms in the formula; the result is the molar mass in g/mol.
How do I revise the mole effectively? Practise mass-to-mole and mole-to-particle conversions, then apply mole ratios from equations before taking the quiz.
Ready to master Cambridge IGCSE Coordinated Science the mole?
Start with the The Mole subtopic page, then book a free trial with a Cambridge IGCSE Coordinated Science specialist to turn mole calculations into guaranteed marks.
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