Motion is how scientists describe the way things change position with time. This MYP Sciences study note covers the difference between distance and displacement, speed and velocity, average vs instantaneous values, the equations of motion, and how to read distance-time and velocity-time graphs — with worked examples and IB MYP-style criterion-A questions.
At a glance
Distance is how far an object has moved; displacement is straight-line distance and direction.
Speed is a scalar (size only); velocity is a vector (size and direction).
Average speed = total distance ÷ total time. Units: m/s.
Acceleration is the rate of change of velocity (m/s²) — positive for speeding up, negative for slowing down.
On a distance-time graph: gradient = speed. Flat line = stationary.
On a velocity-time graph: gradient = acceleration. Area under graph = distance travelled.
Equations of motion link u, v, a, s and t (used when acceleration is constant).
Free fall acceleration on Earth is g ≈ 9.8 m/s² (often taken as 10 m/s² for quick checks).
What you’ll learn
Mapped to the IB MYP Sciences subject guide (2026 onwards).
MYP Sciences A (Knowing and Understanding) — Define distance, displacement, speed, velocity and acceleration with correct units.
MYP Sciences A — Distinguish between scalar and vector quantities, giving examples of each.
MYP Sciences A — Use the equations v = u + at, s = ut + ½at² and v² = u² + 2as for uniformly accelerated motion.
MYP Sciences B (Inquiring and Designing) — Plan a fair-test investigation to measure the acceleration of a moving trolley.
MYP Sciences C (Processing and Evaluating) — Plot and interpret distance-time and velocity-time graphs; identify gradient and area as physical quantities.
MYP Sciences D (Reflecting on the Impacts of Science) — Evaluate how speed-measurement technology (radar, GPS) is used in road safety and sport.
Distance vs displacement — why direction matters
Distance is the total path length; displacement is the straight-line shortcut, with a direction attached.
Imagine you walk 400 m east to a friend's house, then 300 m back west to a café in between. How far did you walk? How far are you from home now?
The distance you walked is the total path length: 400 + 300 = 700 m. The displacement is your final position relative to your start point — only 100 m east of home. Distance has only a size (it is a scalar); displacement has both size and direction (it is a vector).
This distinction matters in MYP Sciences. Examiners often build questions around someone moving in two directions and then ask separately for distance and displacement. They are usually different numbers.
Diagram showing a person walking 400 m east then 300 m west, with distance 700 m and displacement 100 m east
Speed, velocity and acceleration
Speed tells you how fast; velocity tells you how fast and in which direction; acceleration tells you how velocity is changing.
Speed is the distance covered per unit time:
speed=timedistance(m/s)
Velocity is the displacement per unit time, so it carries a direction:
Reading a distance-time graph
The gradient (steepness) of a distance-time graph tells you the speed.
A distance-time graph plots how far an object has travelled (y-axis) against time (x-axis).
Distance-time graph showing three regions: constant speed, stationary, then faster constant speed
A straight, sloping line = constant speed. The steeper the line, the faster the object.
A horizontal (flat) line = stationary (distance is not changing).
A curve that gets steeper = speeding up (accelerating).
A curve that gets less steep = slowing down (decelerating).
The gradient of any straight section gives the speed for that section:
Reading a velocity-time graph
The gradient gives acceleration; the area under the line gives the distance travelled.
A velocity-time graph plots velocity (y-axis) against time (x-axis). It looks similar to a distance-time graph but tells you something different.
Velocity-time graph with three sections: acceleration, constant velocity and deceleration
Two key relationships:
Gradient = acceleration: a positive slope means speeding up, a negative slope means slowing down, and a horizontal line means constant velocity.
Area under the graph = distance travelled. To find the distance for a curve, break it into triangles and rectangles, then add the areas.
For the simple example above with three straight regions, the area is the trapezium shape highlighted — its area equals the total distance the object covered.
Tip: if examiners ask for displacement rather than distance, areas below the x-axis (negative velocity) count as negative and partly cancel the positive area above.
Equations of motion (uniform acceleration)
When acceleration is constant, four equations let you swap between u, v, a, s and t.
For an object moving in a straight line with constant acceleration, the following equations apply:
Symbol
Meaning
Unit
u
initial velocity
m/s
v
final velocity
m/s
a
acceleration
m/s²
s
displacement (or distance, on a straight line)
m
t
time taken
s
The three core equations of motion (often called the "suvat" equations):
v=u+at
Investigating motion in the lab (criterion B and C)
Light gates, ticker timers and video analysis let you measure velocity and acceleration directly.
MYP Sciences criteria B (Inquiring and Designing) and C (Processing and Evaluating) often involve a motion investigation. Three common methods:
Light gates — a beam of infrared light is broken twice by a "double interrupt card" on a moving trolley. The data logger times each break and calculates instantaneous velocity from the card length and the time gap. Two gates give acceleration.
Ticker timer — a tape attached to a trolley is pulled through a vibrating ticker that prints 50 dots per second. Counting dots between intervals gives distance per unit time → velocity, and changes in dot-spacing give acceleration.
Video analysis — record motion at a known frame rate (e.g. 30 fps) and use software (e.g. Tracker) to mark the position each frame. Distance per frame ÷ frame time = velocity.
A good investigation report follows the MYP Sciences criteria:
Criterion C: organised raw data, repeated readings, mean values, suitable graph, calculated gradients with units.
Criterion D: evaluation of accuracy, anomalous results, sources of systematic vs random error, and the wider impact (e.g. how this matters for road safety design).
Light gates measure instantaneous velocity by timing the interrupt card.
Ticker timers print 50 dots per second on a moving tape.
Video analysis works well for slower or rolling motion.
Strong MYP reports identify independent, dependent and controlled variables.
Quick recap
Distance is scalar (size only); displacement is a vector (size and direction).
Acceleration = (v − u) ÷ t. Units m/s². Negative = slowing down.
On a distance-time graph, gradient = speed.
On a velocity-time graph, gradient = acceleration and area = distance.
Use suvat equations only when acceleration is constant.
Free fall on Earth: g ≈ 9.8 m/s² downwards (often taken as 10 m/s²).
Memorise this
Verbatim phrases and definitions MYP criterion-A markschemes credit.
Speed = distance ÷ time (units m/s)
Velocity = displacement ÷ time (units m/s, direction)
Acceleration a = (v − u) ÷ t (units m/s²)
v = u + at
s = ut + ½at²
v² = u² + 2as
g ≈ 9.8 m/s² (Earth's surface)
How it’s examined
The IB MYP Sciences on-screen e-assessment (year 5) tests motion concepts mostly through criterion A (Knowing & Understanding) multiple-choice and short-response items, and through criterion C (Processing & Evaluating) where you interpret motion graphs, calculate values from given data, and identify the meaning of gradient and area. Year 4 internal assessments often build a full lab report on motion measurement, covering criteria B, C and D.
Sources: IB MYP Sciences guide (IBO, official subject guide); IB MYP Sciences subject brief (IBO public PDF); IB MYP Sciences eAssessment specimen materials (IBO, publicly available). Last reviewed 2026-05-25.
Step-by-step worked examples — Motion
Step-by-step solutions to past-paper-style questions on motion, written exactly the way a tutor would explain them at the board.
1Distance vs displacement on a walk
Getting started• scalar vs vector, displacement
▼
Question
A jogger runs 500 m east along a straight road, then turns around and jogs 200 m west. Find the total distance and the displacement from the start.
Step-by-step solution
Step 1
Distance is the total length of the path travelled. Add the two legs: 500 + 200 = 700 m.
Step 2
Displacement is the straight-line position relative to the start, with direction. 500 m east − 200 m west = 300 m east.
Answer
Distance = 700 m; displacement = 300 m east.
Examiner tip
Always state direction when asked for displacement — without it, the answer is incomplete.
2Average speed on a journey
Getting started• speed, v = d/t
▼
Question
A car travels 180 km in 2.5 hours. Calculate the average speed in (a) km/h and (b) m/s.
Step-by-step solution
Step 1
Use speed = distance ÷ time.
v=d/t
3Calculating acceleration
Building confidence• acceleration
▼
Question
A cyclist accelerates from rest to 8 m/s in 4 seconds. Calculate the acceleration.
Step-by-step solution
Step 1
Use a = (v − u) ÷ t with u = 0 (starting from rest), v = 8 m/s, t = 4 s.
a=(8
4Using v² = u² + 2as
Building confidence• suvat, acceleration
▼
Question
A car decelerates uniformly from 25 m/s to 5 m/s over a distance of 60 m. Find the magnitude of the acceleration.
Step-by-step solution
Step 1
Pick the suvat equation that contains u, v, a and s (no t).
v
5Distance from a velocity-time graph
Stretch• v-t graph, area
▼
Question
A vehicle accelerates uniformly from 0 to 12 m/s in 6 s, cruises at 12 m/s for 8 s, then decelerates uniformly to rest in 4 s. Use the velocity-time graph to find the total distance travelled.
Step-by-step solution
Step 1
Split the v-t graph into three regions and find each area (= distance).
Step 2
Region 1 (accelerating triangle): ½ × 6 × 12 = 36 m.
Step 3
Region 2 (cruise rectangle): 8 × 12 = 96 m.
Step 4
Region 3 (deceleration triangle): ½ × 4 × 12 = 24 m.
Step 5
Total distance = 36 + 96 + 24 = 156 m.
Key Formulae — Motion
The formulae you need to memorise for motion on the IB MYP Sciences paper, with every variable defined in plain English and a note on when to use it.
Speed
v=d/t
v
speed (m/s)
d
distance (m)
t
time (s)
When to use
For constant or average speed of an object — distance covered per unit time.
Acceleration
a=(v−u)/t
a
acceleration (m/s²)
First equation of motion
v=u+at
v
final velocity (m/s)
u
Second equation of motion
s=ut+(1/2)at2
Third equation of motion
v2=u2+2as
Key Definitions and Keywords — Motion
Definitions to memorise and the exact keywords mark schemes credit for motion answers — sharpened from recent examiner reports for the 2026 IB MYP Sciences sitting.
Distance
Examiner keyword
The total length of the path travelled by an object. A scalar quantity, measured in metres (m).
Displacement
Examiner keyword
The straight-line distance from the start to the end position, including direction. A vector quantity, measured in metres (m).
Example
If you walk 4 m east then 3 m north, your displacement is 5 m at 37° north of east — even though the distance walked is 7 m.
Speed
Examiner keyword
The distance an object travels per unit time. A scalar, measured in metres per second (m/s).
Velocity
Examiner keyword
The displacement per unit time. A vector — speed with direction — measured in m/s.
Acceleration
Examiner keyword
The rate of change of velocity. A vector, measured in m/s². Negative values indicate deceleration (slowing down).
Uniform (constant) acceleration
Acceleration that does not change with time, so velocity increases (or decreases) at a steady rate.
Scalar quantity
A physical quantity with magnitude only — no direction.
Example
Distance, speed, time, mass and energy are scalars.
Vector quantity
A physical quantity with both magnitude AND direction.
Example
Displacement, velocity, acceleration and force are vectors.
Gradient (of a graph)
Examiner keyword
The change in the y-quantity divided by the change in the x-quantity. On distance-time graphs, gradient = speed; on velocity-time graphs, gradient = acceleration.
Area under a velocity-time graph
Examiner keyword
Equal to the distance travelled. Found by adding the areas of triangles, rectangles and trapeziums under the line.
Common Mistakes and Misconceptions — Motion
The traps other students keep falling into on motion questions — taken from recent IB MYP Sciences examiner reports and mark schemes — and how to avoid them.
✕Treating distance and displacement as the same quantity.
▼
Why it happens
In everyday English the two words are interchangeable, so students assume the same in science.
How to avoid it
Distance is the total path walked; displacement is the straight-line shortcut, with a direction. If the object returns to its start, distance is non-zero but displacement is zero.
✕Forgetting to give the direction when stating a velocity.
▼
Why it happens
Speed and velocity look similar on a calculator (both in m/s), and the direction is easily missed.
How to avoid it
Velocity = magnitude + direction. Always end your answer with a direction ("east", "upwards", "down the slope") or a sign (+/−) on a 1-D axis.
✕Believing that a fast-moving object must have a large acceleration.
▼
Why it happens
In everyday language we say a car "accelerates" when it's going fast.
How to avoid it
Acceleration is the change in velocity per second. A car at a steady 100 km/h has zero acceleration. Only when velocity is changing is there a non-zero acceleration.
✕Mixing units inside a suvat equation — e.g. distance in km and time in s.
▼
Why it happens
Question stems often state distance in km, time in minutes or hours, mass in grams.
How to avoid it
Convert everything to SI base units (m, s, kg, m/s, m/s²) BEFORE substituting. Write the converted values down so you don't lose track.
✕Confusing a velocity-time graph with a distance-time graph.
▼
Why it happens
Both have time on the x-axis, look like straight lines, and use the word 'gradient'.
How to avoid it
Read the y-axis label. On a d-t graph the gradient = speed and a horizontal line = stationary. On a v-t graph the gradient = acceleration and a horizontal line = constant velocity.
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6
Investigating motion in the lab (criterion B and C)
A useful test: if the question asks "how far?", they usually want distance. If it asks "how far from start?" or "what is the resultant?", they want displacement.
Distance = total path travelled. Scalar. No direction.
Displacement = straight-line distance from start to finish, with direction. Vector.
If an object returns to its starting point, displacement is zero but distance is not.
velocity=timedisplacement(m/s, with direction)
Two cyclists pedalling at 5 m/s on the same straight road have equal speeds, but if they are heading in opposite directions their velocities are equal in size and opposite in sign (e.g. +5 m/s vs −5 m/s).
Acceleration is how quickly velocity changes:
a=tv−u(m/s²)
where u is the starting velocity and v is the velocity after time t. If a car accelerates from 5 m/s to 25 m/s in 4 s, a = (25 − 5) ÷ 4 = 5 m/s².
Acceleration can be negative — this means the object is slowing down (often called deceleration) or speeding up in the opposite direction. MYP examiners like to test whether you understand that a negative value still describes a real acceleration.
Acceleration (m/s²) = change in velocity ÷ time taken.
Negative acceleration = slowing down (or accelerating in the opposite direction).
speed=runrise=ΔtimeΔdistance
In the diagram above, region A might be 60 m in 3 s = 20 m/s. Region B has zero gradient, so the object is at rest. Region C is steeper than A, so the object is moving faster.
Gradient = acceleration. Horizontal line = constant velocity.
Area under graph = distance travelled (or displacement, with sign).
s=ut+21at2
v2=u2+2as
Choose the equation that contains the three quantities you know and the one you want to find.
Worked example. A cyclist accelerates from 4 m/s to 12 m/s in 5 s along a straight path.
Acceleration: a = (v − u) ÷ t = (12 − 4) ÷ 5 = 1.6 m/s².
Distance covered: s = ut + ½at² = (4 × 5) + ½(1.6)(5²) = 20 + 20 = 40 m.
For free fall on Earth (no air resistance), acceleration a = g = 9.8 m/s² downwards. A dropped ball from rest after 2 s has v = 0 + 9.8 × 2 = 19.6 m/s.
Use the suvat equations only when acceleration is constant.
v = u + at links velocity to time.
s = ut + ½at² links distance to time.
v² = u² + 2as lets you skip time when you don't know it.
For criterion D, link motion measurement to real-world technology: GPS receivers calculate velocity from the rate of change of position from multiple satellites; radar guns calculate it from the Doppler shift in reflected microwaves. Both depend on accurately measuring small time intervals.
=
180/2.5
Step 2
180 ÷ 2.5 = 72 km/h.
Step 3
To convert km/h → m/s, divide by 3.6 (because 1 km = 1000 m and 1 h = 3600 s).