Tutopiya: Study Resources for IGCSE, IB, GCSE & A-Levels

Practice progress

5 MCQs

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1
In Fleming's left-hand rule, the second finger represents:
Answer & explanation
Correct: option C
First finger = Field; seCond finger = Current; thuMb = Motion. Use conventional current (+ → −).
2
A wire of length 0.10 m carries 2.0 A perpendicular to a field of 0.50 T. The force on the wire is:
Answer & explanation
Correct: option B
F = BIL = 0.50 × 2.0 × 0.10 = 0.10 N.
3
Which of the following would NOT change the direction of the force on a current-carrying wire in a magnetic field?
Answer & explanation
Correct: option C
Reverse only one → force reverses. Reverse both → force returns to original direction (two negatives cancel).
4
A wire is placed parallel to a strong magnetic field and a current is switched on. The force on the wire is:
Answer & explanation
Correct: option C
Parallel wire → no perpendicular component of B → F = 0.
5
A 4.0 cm length of wire in a 0.25 T field experiences a force of 0.20 N when current flows. What is the current?
Answer & explanation
Correct: option C
I = F/(BL) = 0.20 / (0.25 × 0.04) = 20 A. Watch the cm → m conversion.