ForcesAQA GCSE Physics (8463)

Forces and Elasticity

Work through the notes, try the practice questions, then take the quiz. The report tells you exactly what to revise next. (2026)

Practice progress

6 MCQs

0 of 6 attempted

Correct

Incorrect

Remaining

1
Hooke's law: F = ke. If F doubles within the elastic limit, e:
Answer & explanation
Correct: option A
Linear: F ∝ e.
2
Spring constant unit:
Answer & explanation
Correct: option C
k = F/e → N/m.
3
Elastic deformation:
Answer & explanation
Correct: option B
Elastic = recoverable.
4
A 200 N/m spring is stretched 5 cm. Energy stored?
Answer & explanation
Correct: option A
E_e = ½ × 200 × 0.05² = 0.25 J.
5
In RP6, the gradient of an F vs e graph gives:
Answer & explanation
Correct: option B
Gradient = F/e = k.
6
Beyond the limit of proportionality, the F-e graph:
Answer & explanation
Correct: option B
No longer linear; extension grows more for each newton (or yields).

ForcesAQA GCSE Physics (8463)

Work through the notes, try the practice questions, then take the quiz. The report tells you exactly what to revise next. (2026)

6 MCQs

0 of 6 attempted

Correct

Incorrect

Remaining

1
Hooke's law: F = ke. If F doubles within the elastic limit, e:
Answer & explanation
Correct: option A
Linear: F ∝ e.
2
Spring constant unit:
Answer & explanation
Correct: option C
k = F/e → N/m.
3
Elastic deformation:
Answer & explanation
Correct: option B
Elastic = recoverable.
4
A 200 N/m spring is stretched 5 cm. Energy stored?
Answer & explanation
Correct: option A
E_e = ½ × 200 × 0.05² = 0.25 J.
5
In RP6, the gradient of an F vs e graph gives:
Answer & explanation
Correct: option B
Gradient = F/e = k.
6
Beyond the limit of proportionality, the F-e graph:
Answer & explanation
Correct: option B
No longer linear; extension grows more for each newton (or yields).