ElectricityAQA GCSE Physics (8463)

Energy Transfers

Work through the notes, try the practice questions, then take the quiz. The report tells you exactly what to revise next. (2026)

Practice progress

6 MCQs

0 of 6 attempted

Correct

Incorrect

Remaining

1
A 230 V kettle draws 11 A. Its power is:
Answer & explanation
Correct: option C
P = VI = 230 × 11 = 2530 W.
2
A 4 A current flows through a 6 Ω resistor. Power dissipated?
Answer & explanation
Correct: option D
P = I²R = 4² × 6 = 16 × 6 = 96 W.
3
A 100 W lamp on 230 V draws what current?
Answer & explanation
Correct: option B
I = P/V = 100/230 ≈ 0.43 A.
4
Doubling the current through a fixed resistor multiplies power dissipated by:
Answer & explanation
Correct: option C
P ∝ I², so doubling I gives ×4.
5
Why does the National Grid transmit at high voltage?
Answer & explanation
Correct: option B
Same power needs less current at high V; less I means much less I²R loss.
6
A 12 V battery drives 0.5 A through a bulb. Bulb power?
Answer & explanation
Correct: option C
P = VI = 12 × 0.5 = 6 W.

ElectricityAQA GCSE Physics (8463)

Work through the notes, try the practice questions, then take the quiz. The report tells you exactly what to revise next. (2026)

6 MCQs

0 of 6 attempted

Correct

Incorrect

Remaining

1
A 230 V kettle draws 11 A. Its power is:
Answer & explanation
Correct: option C
P = VI = 230 × 11 = 2530 W.
2
A 4 A current flows through a 6 Ω resistor. Power dissipated?
Answer & explanation
Correct: option D
P = I²R = 4² × 6 = 16 × 6 = 96 W.
3
A 100 W lamp on 230 V draws what current?
Answer & explanation
Correct: option B
I = P/V = 100/230 ≈ 0.43 A.
4
Doubling the current through a fixed resistor multiplies power dissipated by:
Answer & explanation
Correct: option C
P ∝ I², so doubling I gives ×4.
5
Why does the National Grid transmit at high voltage?
Answer & explanation
Correct: option B
Same power needs less current at high V; less I means much less I²R loss.
6
A 12 V battery drives 0.5 A through a bulb. Bulb power?
Answer & explanation
Correct: option C
P = VI = 12 × 0.5 = 6 W.