Summary
Sulfur is used in the manufacture of sulfuric acid through a series of reactions involving sulfur dioxide and sulfur trioxide. The process is known as the Contact Process.
- Sulfur Dioxide — a gas formed by burning sulfur in air. Example: S (s) + O2 (g) → SO2 (g)
- Sulfur Trioxide — a gas formed by reacting sulfur dioxide with oxygen. Example: 2SO2 (g) + O2 (g) ⇋ 2SO3 (g)
- Oleum — a thick fuming liquid formed by dissolving sulfur trioxide in concentrated sulfuric acid. Example: Used to safely produce sulfuric acid by mixing with water
- Sulfuric Acid — a strong acid formed by reacting sulfur trioxide with water. Example: H2O (l) + SO3 (g) → H2SO4 (aq)
Exam Tips
Key Definitions to Remember
- Sulfur Dioxide: A gas formed by burning sulfur in air
- Sulfur Trioxide: A gas formed by reacting sulfur dioxide with oxygen
- Oleum: A thick fuming liquid formed by dissolving sulfur trioxide in concentrated sulfuric acid
- Sulfuric Acid: A strong acid formed by reacting sulfur trioxide with water
Common Confusions
- Confusing sulfur dioxide with sulfur trioxide
- Misunderstanding the role of Oleum in the process
Typical Exam Questions
- What is the first step in the Contact Process? Sulfur is burned in air to form sulfur dioxide
- Why is sulfur trioxide dissolved in concentrated acid instead of water? To avoid forming a thick and dangerous mist of acid
- What conditions are used to convert sulfur dioxide to sulfur trioxide? Temperature of around 450°C, pressure of 2 atm, and catalyst vanadium(V) oxide
What Examiners Usually Test
- Steps involved in the Contact Process
- Conditions required for the conversion of sulfur dioxide to sulfur trioxide
- Safety reasons for using Oleum instead of water