Study Notes
Similarity in geometry refers to figures having the same shape but not necessarily the same size, with corresponding angles equal and sides in proportion. Example: Two triangles with angles 60°, 60°, 60° and sides 3 cm, 3 cm, 3 cm and 6 cm, 6 cm, 6 cm are similar.
- Pythagoras' Theorem — relates the lengths of the sides of a right triangle: a² + b² = c². Example: In a triangle with sides 8 cm and 9 cm, the hypotenuse is √17 cm.
- Congruence — two figures are congruent if they are the same size and shape. Example: Two triangles with sides 5 cm, 5 cm, 8 cm and 5 cm, 5 cm, 8 cm are congruent.
- Scale Factor — the ratio of corresponding side lengths in similar figures. Example: If the side of one triangle is 3 cm and the corresponding side of a similar triangle is 6 cm, the scale factor is 2.
- Area Ratio — for similar figures, the ratio of areas is the square of the scale factor. Example: If the scale factor is 2, the area ratio is 4.
- Volume Ratio — for similar 3D objects, the ratio of volumes is the cube of the scale factor. Example: If the scale factor is 1.5, the volume ratio is 3.375.
Exam Tips
Key Definitions to Remember
- Similarity: Figures with the same shape but different sizes.
- Pythagoras' Theorem: a² + b² = c² for right triangles.
- Congruence: Figures that are identical in size and shape.
- Scale Factor: Ratio of corresponding side lengths in similar figures.
Common Confusions
- Confusing similarity with congruence.
- Misapplying Pythagoras' Theorem to non-right triangles.
Typical Exam Questions
- How do you determine if two triangles are similar? Check if corresponding angles are equal and sides are proportional.
- What is the scale factor if one triangle's side is 3 cm and the similar triangle's side is 6 cm? The scale factor is 2.
- How do you find the area of a similar figure if the scale factor is 3? Multiply the original area by 9 (3²).
What Examiners Usually Test
- Understanding of similarity and congruence.
- Ability to apply Pythagoras' Theorem correctly.
- Calculating scale factors and using them to find area and volume ratios.