Case 1: leading coefficient 1. Factorise x2+bx+c as (x+p)(x+q) where pq=c and p+q=b.
Worked example. Factorise x2+7x+12.
- Need two numbers that multiply to 12 and add to 7.
- 3Γ4=12 and 3+4=7. β
- x2+7x+12=(x+3)(x+4).
Worked example. Factorise x2β5x+6.
- Multiply to 6, add to β5.
- Both factors must be NEGATIVE (so product positive, sum negative): β2Γβ3=6, β2+β3=β5. β
- x2β5x+6=(xβ2)(xβ3).
Worked example. Factorise x2βxβ12.
- Multiply to β12, add to β1.
- One positive, one negative. β4Γ3=β12 and β4+3=β1. β
- x2βxβ12=(xβ4)(x+3).
Case 2: leading coefficient ξ =1 (Extended). Factorise ax2+bx+c.
Use the AC method:
- Multiply aΓc.
- Find two numbers that multiply to ac and add to b.
- Split the middle term using those numbers.
- Factor by grouping.
Worked example. Factorise 2x2+7x+3.
- aΓc=2Γ3=6.
- Two numbers multiplying to 6 and adding to 7: 6Γ1=6, 6+1=7. β
- Split: 2x2+6x+x+3.
- Group: 2x(x+3)+1(x+3)=(x+3)(2x+1).
So 2x2+7x+3=(x+3)(2x+1).
Always check by expanding!