Structure of a metal (spec 1.70)
Positive ions in a sea of delocalised electrons.
When metal atoms come together to form a solid, each atom loses its outer-shell electrons. The remaining positively-charged ions arrange in a regular 3D lattice. The lost electrons no longer belong to any individual atom — they become delocalised and form a 'sea' or 'cloud' that surrounds the cations.
Example — magnesium.
- Electron configuration of an Mg atom: 2, 8, 2 — 2 outer electrons.
- Each Mg atom loses BOTH outer electrons.
- Result: Mg²⁺ ions in a lattice + 2 delocalised electrons per atom.
Example — aluminium.
- Electron configuration of an Al atom: 2, 8, 3 — 3 outer electrons.
- Each Al atom loses ALL 3 outer electrons.
- Result: Al³⁺ ions + 3 delocalised electrons per atom.
The more outer-shell electrons each atom contributes, the denser the 'electron sea' — and (other things being equal) the stronger the metallic bond. This is why aluminium melts at 660 °C and magnesium at 650 °C, while sodium (only 1 outer electron) melts at just 98 °C.
Visualising the lattice. Picture rows and columns of positive 'balls' (the cations), with negatively-charged 'mist' (the delocalised electrons) filling every gap between them. The positive ions are arranged regularly — in some metals (like Cu, Ag) the ions are close-packed in layers; in others (like Fe) the arrangement is body-centred cubic — but the key idea is the same: regular lattice + delocalised electron sea.
Why the structure is stable. Each positive ion is attracted to the cloud of negative delocalised electrons around it — these electrostatic forces extend in every direction throughout the lattice. The whole structure is held together by this 'glue' of attraction.
- Each metal atom loses its outer electrons.
- Cations form a regular 3D lattice.
- Released electrons become DELOCALISED — free to move throughout the structure.
- More outer electrons lost → stronger metallic bond (typically).