Detailed notes on Number for Cambridge Lower Secondary Mathematics, covering key concepts, explanations, examples, and exam-focused revision points.
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Powers and Roots — Cambridge Lower Secondary Maths, Grade 8
You already know the three index laws. Stage 9 stretches them — a power of zero, negative indices that mean fractions, and using every law together inside longer simplifications without losing track of a single index.
At a glance
Multiplying powers of the same base adds the indices: am×an=am+n.
Dividing powers of the same base subtracts the indices: am÷an=am−n.
Raising a power to a power multiplies the indices: (am)n=amn.
Any non-zero number to the power 0 equals 1, so a0=1.
A negative index means a reciprocal: a−n=an1.
The index laws only ever work when the base is the same.
A square root undoes squaring; a cube root undoes cubing.
Estimate a root by trapping it between two perfect squares or cubes.
What you’ll learn
Mapped to the Cambridge Lower Secondary Mathematics curriculum framework.
Stage 9 — Apply all three laws of indices fluently within longer simplifications.
Stage 9 — Use the zero index, explaining why any non-zero number to the power 0 is 1.
Stage 9 — Use negative indices and convert between a−n and an.
The index laws, used fluently
All three laws should now run together inside a single longer simplification.
By Stage 9 the three laws of indices should be second nature. The new skill is using them together — a single expression often needs more than one law before it is fully simplified.
The three laws, all needing the same base:
Multiplying: am×an=a — add the indices.
The zero index
Any non-zero number raised to the power 0 equals 1 — and the dividing law shows why.
What does a power of zero mean? You cannot multiply a number "zero times", so the meaning comes from the dividing law instead.
Think about a4÷a4. A number divided by itself is 1. But the dividing law says . Both lines describe the same calculation, so must equal .
Negative indices
A negative index means a reciprocal — flip the base under 1.
Carry the halving pattern past zero. After 21=2 and 20=1, dividing by 2 again gives , then . A means a .
Roots and estimating them
Roots undo powers — trap an awkward root between two perfect values.
A root undoes a power. The square root asks "what was squared?" — since 92=81, 81. The asks "what was cubed?" — since , .
Combining the laws in one go
Harder questions chain several laws together — work one step at a time.
The toughest Stage 9 index questions ask you to simplify an expression that needs several laws in turn. The cure is the same as always: one step per line.
Try 212(2.
Where you'll use this next
Index fluency, especially negative indices, underpins standard form and algebra.
Confident work with powers and roots opens up a great deal of later maths:
Standard form depends entirely on powers of 10, and small numbers use the negative indices you have just met.
Algebra uses the index laws constantly — simplifying x5÷x2 to x is the very same rule you used with numbers.
Quick recap
Multiplying powers of the same base adds the indices.
Dividing powers of the same base subtracts the indices.
Raising a power to a power multiplies the indices.
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1
Stage 9 — Estimate square and cube roots of numbers that are not perfect.
Where you'll use this next
m+n
Dividing: am÷an=am−n — subtract the indices.
Power of a power: (am)n=amn — multiply the indices.
Add, subtract, multiply — one operation for each law.
Take 2325×24. Multiply on the top first: 25×24=29. Then divide: 29÷23=26. Naming which law you are using at each step keeps a longer simplification under control.
Multiplying powers of the same base adds the indices.
Dividing powers of the same base subtracts the indices.
A power of a power multiplies the indices.
Longer expressions often need two or three laws in turn.
a4÷a4=a4−4=a0
a0
1
The dividing law forces $a^0$ to equal 1.
So 70=1, 1000=1 and even (−3)0=1. The base does not matter, as long as it is not zero — 00 is left undefined and you will not be asked for it.
This is genuinely useful inside the index laws. When the indices subtract to zero, you can write the answer as 1 straight away, instead of leaving it as a0.
Any non-zero number to the power 0 equals 1.
The dividing law gives the reason: an÷an=a0=1.
The base can be any non-zero number, including a negative.
When indices subtract to 0, write the answer as 1.
2−1=21
2−2=41
negative index
reciprocal
The rule is a−n=an1.
A negative index keeps the halving pattern going.
So 3−2=321=91 and 10−3=10001. A negative index does not make the answer negative — it makes a fraction less than 1.
The index laws all still work. 25÷28=25−8=2−3, which is 81. Subtracting a bigger index simply lands you on a negative one.
A negative index means a reciprocal: a−n=an1.
3−2=91 — a fraction, not a negative number.
All three index laws still apply with negative indices.
Subtracting a larger index gives a negative index.
=
9
cube root
43=64
364=4
Most numbers are not perfect squares, so their roots are not whole numbers. The Stage 9 skill is estimating such a root by trapping it between two perfect squares you know.
$\sqrt{50}$ sits just above 7, because 50 is just above 49.
To estimate 50: since 72=49 and 82=64, the answer lies between 7 and 8. As 50 is very close to 49, 50 is a little above 7 — about 7.1.
Knowing the squares to 152=225 and the cubes to 53=125 makes both finding and estimating roots far quicker.
A square root undoes squaring; a cube root undoes cubing.
Most roots are not whole numbers.
Trap a root between two perfect squares or cubes you know.
Learn the squares to 225 and the cubes to 125.
3
)2
×
24
Power of a power first:(23)2=26.
Multiply on the top:26×24=210.
Divide:210÷212=2−2.
Write the negative index as a fraction:2−2=41.
Each line uses one index law — the expression shrinks safely.
When you finish, sense-check the index: a negative final index means an answer below 1, a positive one means an answer above 1. If the size feels wrong, an index has slipped.
Hard questions need several index laws used in turn.
Do one law per line, naming which law each time.
Settle brackets and powers of powers first.
Sense-check whether the final index is positive or negative.
3
Area and volume rest on squares and cubes, and roots reverse them to find a missing length.
Calculator work asks you to estimate first, so trapping a root between perfect values is a real safety net.
If a later topic with powers feels shaky, a quick refresh of the three laws, the zero index and negative indices usually clears it up. Accuracy beats speed every time.
Standard form uses powers of 10 and negative indices.
Algebra reuses the index laws to simplify expressions.
Area and volume rest on squares, cubes and their roots.
Estimating roots is a safety net for calculator work.
1
A square root undoes squaring; a cube root undoes cubing.
Estimate an awkward root by trapping it between perfect values.
+
2
=
58
Step 2
Now divide — subtract the indices.
58÷53=58−3=55
Step-by-step solution
Step 1
Any non-zero number to the power 0 equals 1, so 90=1.
90=1
Step 2
The same rule gives 40=1.
40=1
Step 3
Add the two values.
1+1=2
Answer
2
2−4=241
Step 2
Work out the power on the bottom.
24=16
Step 3
So the fraction is one sixteenth.
2−4=161
Answer
161
Step-by-step solution
Step 1
Find the perfect squares either side of 70.
82=64,92=81
Step 2
Since 70 is between 64 and 81, the root lies between 8 and 9.
Step 3
70 is fairly close to 64, so the root is a little above 8 — about 8.4.
Answer
70 lies between 8 and 9, and is roughly 8.4
11
(32)3×32
Step-by-step solution
Step 1
Power of a power first — multiply the indices.
(32)3=32×3=36
Step 2
Multiply on the top — add the indices.
36×32=38
Step 3
Divide — subtract the indices.
38÷311=38−11
Step 4
A negative index means a reciprocal.
3−3=331
Answer
271
=
125
0
=
1
1
Example
2−3=81.
1
72=49
=
3
33=27
3
+
4
=
27
2−3=231=81
▼
Why it happens
An index of zero looks like it should produce an answer of zero.
How to avoid it
The dividing law gives an÷an=a0, and a number over itself is 1, so a0=1.
The index laws only work when the base is the same. 23×52 cannot be combined.
The index is read as a multiplier rather than a count of factors.
How to avoid it
The index counts factors, so 34=3×3×3×3=81.
=
3−3
=
271
Power and Roots — Cambridge Lower Secondary Mathematics — Stage 9 Revision Notes & Practice | Tutopiya