What is Standard Form in Mathematics?

In Mathematics, particularly at the Cambridge Lower Secondary level, Standard Form is a way of writing very large or very small numbers using powers of ten. It is expressed as a number between 1 and 10 multiplied by a power of ten. For example, 4,500 can be written in Standard Form as 4.5 x 10^3.

How do you convert a number into Standard Form?

To convert a number into Standard Form, first identify the most significant digit and place the decimal point after it. Count how many places the decimal has moved from its original position to determine the power of ten. For example, to convert 0.00056 to Standard Form, move the decimal 4 places to the right, resulting in 5.6 x 10^-4.

Why is Standard Form useful in Mathematics?

Standard Form is particularly useful in Mathematics for simplifying calculations with very large or very small numbers. It makes it easier to read, compare, and perform arithmetic operations, which is especially beneficial in scientific and engineering contexts.

What are some common mistakes to avoid when using Standard Form?

Common mistakes include not placing the decimal point correctly, using an incorrect power of ten, and failing to ensure the number is between 1 and 10. It's important to double-check these aspects to ensure accuracy in Standard Form.

How does Standard Form relate to scientific notation?

Standard Form is essentially the same as scientific notation, which is commonly used in scientific fields. Both formats express numbers as a product of a number between 1 and 10 and a power of ten, making them interchangeable in most contexts.

Why is "Leaving the coefficient outside the range $1 \le a < 10$, e.g. writing $52{,}000 = 52 \times 10^3$." a common mistake in Standard Form?

Why it happens: The decimal point is only moved part of the way before the answer is written down. How to avoid it: Always slide the decimal point until there is exactly one non-zero digit in front of it. 52,000 = 5.2 × 10^4.

Why is "Using a positive power for a small number or a negative power for a large one." a common mistake in Standard Form?

Why it happens: The sign is chosen from habit rather than from the size of the number. How to avoid it: Check the size of the answer: bigger than 10 → positive power, smaller than 1 → negative power, between 1 and 10 → power of zero.

Why is "Adding the powers of ten when adding numbers, e.g. $4 \times 10^3 + 2 \times 10^3 = 6 \times 10^6$." a common mistake in Standard Form?

Why it happens: The index law for multiplication is over-applied to addition. How to avoid it: Powers only combine in multiplication and division. For addition, match the powers first and then add the coefficients only.

Why is "Stopping at $14 \times 10^5$ and calling it standard form." a common mistake in Standard Form?

Why it happens: After multiplying coefficients the answer is written down without a final check. How to avoid it: Inspect the coefficient at the end. If it is outside 1 a < 10, slide the decimal point and balance the power: 14 × 10^5 = 1.4 × 10^6.

Why is "Getting the power one out, e.g. writing $0.0042 = 4.2 \times 10^{-2}$." a common mistake in Standard Form?

Why it happens: Hops of the decimal point are counted starting from one rather than from zero, or the leading zero is included by accident. How to avoid it: Count each move of the decimal point carefully. 0.0042 needs three moves to reach 4.2, so the answer is 4.2 × 10^-3.

NumberCambridge Lower Secondary Mathematics — Checkpoint

Standard Form

Q: Why is "Leaving the coefficient outside the range $1 \le a < 10$, e.g. writing $52{,}000 = 52 \times 10^3$." a common mistake in Standard Form?

Why it happens: The decimal point is only moved part of the way before the answer is written down. How to avoid it: Always slide the decimal point until there is exactly one non-zero digit in front of it. 52,000 = 5.2 × 10^4.

Q: Why is "Using a positive power for a small number or a negative power for a large one." a common mistake in Standard Form?

Why it happens: The sign is chosen from habit rather than from the size of the number. How to avoid it: Check the size of the answer: bigger than 10 → positive power, smaller than 1 → negative power, between 1 and 10 → power of zero.

Q: Why is "Adding the powers of ten when adding numbers, e.g. $4 \times 10^3 + 2 \times 10^3 = 6 \times 10^6$." a common mistake in Standard Form?

Why it happens: The index law for multiplication is over-applied to addition. How to avoid it: Powers only combine in multiplication and division. For addition, match the powers first and then add the coefficients only.

Q: Why is "Stopping at $14 \times 10^5$ and calling it standard form." a common mistake in Standard Form?

Why it happens: After multiplying coefficients the answer is written down without a final check. How to avoid it: Inspect the coefficient at the end. If it is outside 1 a < 10, slide the decimal point and balance the power: 14 × 10^5 = 1.4 × 10^6.

Q: Why is "Getting the power one out, e.g. writing $0.0042 = 4.2 \times 10^{-2}$." a common mistake in Standard Form?

Why it happens: Hops of the decimal point are counted starting from one rather than from zero, or the leading zero is included by accident. How to avoid it: Count each move of the decimal point carefully. 0.0042 needs three moves to reach 4.2, so the answer is 4.2 × 10^-3.

Work through the notes, try the practice questions, then take the quiz. The report tells you exactly what to revise next.

Previous Next

Learn this Topic

Start with the slides for the quick version, then go deeper with the full study notes.

Short Study Notes in the form of Slides

Read the notes first. If the method in a worked example clicks, you're ready for the questions.

Short Study Notes — Standard Form

Start with these resources to cover the key concepts, then work through the practice questions.

Page 1 / 0

Detailed Notes

Clear explanations, examples and a recap to help you really understand this topic.

Take these study notes with you

Download a branded PDF — full prose, callouts, recap and memorise list for Standard Form, ready to print or save offline.

Standard Form — Cambridge Lower Secondary Maths, Checkpoint

Revise how to write enormous and tiny numbers in standard form, switch back to ordinary form in a flash, and add, subtract, multiply and divide with them — so any place value becomes easy to handle before your Checkpoint.

What you’ll learn

Mapped to the Cambridge Lower Secondary Mathematics curriculum framework.

Write very large and very small numbers in standard form $a \times 10^n$ .
Convert numbers between standard form and ordinary form fluently.
Multiply and divide numbers in standard form using the index laws.
Solve real-life problems involving distances, masses and other quantities written in standard form.

What standard form looks like

Every number in standard form has the same shape — one digit before the point, then a power of ten.

Standard form (also called scientific notation) is a tidy way of writing very large or very small numbers. Every number in standard form has the same shape:

$a \times 10^n$

with two rules to remember:

$a$ is a number with exactly one non-zero digit before the decimal point, so $1 \le a < 10$ .
$n$ is an integer — it can be positive, negative or zero.

So $6.2 \times 10^5$ and $3.07 \times 10^{-2}$ are written correctly, but $0.62 \times 10^6$ and $62 \times 10^4$ are not — the $a$ part is in the wrong range. Fix them by sliding the decimal point and adjusting the power: $0.62 \times 10^6 = 6.2 \times 10^5$ and $62 \times 10^4 = 6.2 \times 10^5$ .

The coefficient sits between 1 and 10; the power of ten does the heavy lifting.

This neat shape means scientists, engineers and your calculator can write huge or tiny quantities without filling the page with zeros. The mass of the Earth becomes a comfortable $5.97 \times 10^{24}$ kg instead of $24$ digits of zeros.

Standard form is always $a \times 10^n$ .
$a$ must be at least 1 and less than 10.
$n$ is a whole-number power — positive, negative or zero.
Slide the decimal point to fix an $a$ that is out of range.

Writing large numbers in standard form

Count how many places the decimal point hops left to find the positive power.

Large numbers go with positive powers of $10$ . The recipe is straightforward:

Put the decimal point so that there is exactly one non-zero digit before it.
Count how many places the point has moved — call that count $n$ .
Multiply by $10^n$ .

Take $74{,}000{,}000$ . The original decimal point sits invisibly at the end. To get $7.4$ you slide the point seven places to the left, so $74{,}000{,}000 = 7.4 \times 10^7$ .

Moving the decimal point left increases the power; the original size is preserved.

Going the other way is just as easy. To write $3.06 \times 10^5$ in ordinary form, slide the decimal point five places to the right, filling in zeros as needed: $3.06 \times 10^5 = 306{,}000$ .

A neat sense-check: a positive power of $10$ should always give a number bigger than $10$ . If your answer comes out small, the power has the wrong sign.

Large number ↔ positive power of $10$ .
Count the places the decimal point moves to the left.
Switch back by moving the point the same number of places to the right.
Positive power should give an answer at least $10$ .

Writing small numbers in standard form

Tiny numbers use a negative power — count how many places the point moves right.

Numbers smaller than $1$ need a negative power of $10$ . The recipe is the mirror image of the one for large numbers:

Slide the decimal point so that there is one non-zero digit in front of it.
Count the places it moved — that count is $-n$ .
Multiply by $10^{-n}$ .

So for $0.00045$ , the point has to slide four places to the right to land just after the $4$ , giving $4.5 \times 10^{-4}$ . Each step right is a division by $10$ , which is why the power comes out negative.

Each step right divides by ten, so the power of ten is negative.

To go back to ordinary form, do the reverse: $9.1 \times 10^{-3}$ means slide the decimal point three places to the left, so $9.1 \times 10^{-3} = 0.0091$ .

The diameter of a red blood cell is about $7 \times 10^{-6}$ m — much friendlier to read than $0.000007$ m.

Small number ↔ negative power of $10$ .
Count the places the decimal point moves to the right.
Switch back by moving the point the same number of places to the left.
A negative power should give an answer smaller than $1$ .

Multiplying and dividing in standard form

Handle the coefficients and the powers of ten separately — then tidy.

When you multiply two numbers in standard form, multiply the coefficients and add the powers:

$(a \times 10^m) \times (b \times 10^n) = (a \times b) \times 10^{m+n}$

So $(3 \times 10^4) \times (2 \times 10^5) = 6 \times 10^9$ .

When you divide, divide the coefficients and subtract the powers:

$(a \times 10^m) \div (b \times 10^n) = (a \div b) \times 10^{m-n}$

So $(8 \times 10^7) \div (2 \times 10^3) = 4 \times 10^4$ .

Always treat the coefficients and the powers of ten separately.

Sometimes the coefficient drifts outside $1 \le a < 10$ . Just tidy at the end:

$(5 \times 10^3) \times (4 \times 10^6) = 20 \times 10^9 = 2.0 \times 10^{10}$ — one extra power because $20 = 2.0 \times 10^1$ .
$(2 \times 10^4) \div (8 \times 10^7) = 0.25 \times 10^{-3} = 2.5 \times 10^{-4}$ — one less power because $0.25 = 2.5 \times 10^{-1}$ .

Doing the index work first and the tidy-up afterwards is the cleanest way to keep mistakes out.

Multiplication: multiply the coefficients and add the powers.
Division: divide the coefficients and subtract the powers.
If $a$ comes out outside $1 \le a < 10$ , adjust the power to tidy.
Keep the two parts separate until the very end.

Adding and subtracting in standard form

Match the powers first, then add or subtract the coefficients.

Adding and subtracting needs a small extra step — the powers of $10$ must be the same before you combine the coefficients. Think of it as the standard-form version of needing a common denominator.

For $4.2 \times 10^5 + 3.1 \times 10^4$ , rewrite the smaller-power number so both share the same power. $3.1 \times 10^4 = 0.31 \times 10^5$ , so:

$4.2 \times 10^5 + 0.31 \times 10^5 = (4.2 + 0.31) \times 10^5 = 4.51 \times 10^5.$

The same idea works for subtraction. For $7 \times 10^{-3} - 4 \times 10^{-4}$ , rewrite the second number as $0.4 \times 10^{-3}$ , then:

$(7 - 0.4) \times 10^{-3} = 6.6 \times 10^{-3}.$

After combining, check the coefficient is back in range. If not, slide the decimal point and adjust the power as before. A quick estimate before you start — "this is about $10^5$ plus a tenth of $10^5$ " — keeps you confident the answer is sensible.

Make the powers of ten match before adding or subtracting.
Rewriting the smaller-power number is usually easier.
Combine the coefficients, keeping the shared power.
Tidy if the coefficient ends up outside $1 \le a < 10$ .

Where you'll use this next

Standard form turns up in science, technology and your calculator screen.

Standard form is one of those skills that quietly powers most of the science you meet later:

In physics and chemistry it expresses huge distances (the Sun is $1.5 \times 10^{11}$ m away) and tiny masses (the mass of an electron is $9.11 \times 10^{-31}$ kg) without scaring anyone.
On your calculator, large or small results appear in standard form automatically — knowing how to read $3.4\mathrm{E}{-5}$ means knowing how to read $3.4 \times 10^{-5}$ .
In data and computing, file sizes, populations and frequencies jump across many powers of ten.

Coming back to this section for a refresher whenever you bump into very big or very small numbers will pay off all the way through your studies.

Science uses standard form for distances, masses and times.
Calculators switch to standard form for extreme values automatically.
Standard form keeps comparison of very different sizes manageable.
Strong fluency here helps every subject that uses measurement.

Sources: Cambridge Lower Secondary Mathematics curriculum framework. Last reviewed 2026-05-19.

Master this Topic

Worked examples, key facts and definitions, and the mistakes to watch out for — everything you need to feel confident with this topic.

Take this whole topic with you

Download a branded revision sheet — worked examples, formulae, definitions and common mistakes for Standard Form, ready to print or save as PDF.

Step-by-step worked examples — Standard Form

Step-by-step solutions for standard form, written exactly the way a tutor would explain them at the board.

1Writing a large number in standard form
Getting started• large numbers, conversion
Question
Write $63{,}000{,}000$ in standard form.
Step-by-step solution
1. Step 1
  Place the decimal point so that there is exactly one non-zero digit in front of it.
  $6.3$
2. Step 2
  Count how many places the decimal point has moved from the original number — here it slid seven places to the left.
3. Step 3
  The number is bigger than $10$ , so the power of ten is positive.
  $63{,}000{,}000 = 6.3 \times 10^7$
Answer
$6.3 \times 10^7$
2Writing a small number in standard form
Getting started• small numbers, conversion
Question
Write $0.0029$ in standard form.
Step-by-step solution
1. Step 1
  Slide the decimal point until there is one non-zero digit in front of it.
  $2.9$
2. Step 2
  Count the moves — the point shifted three places to the right.
3. Step 3
  The number is less than $1$ , so the power of ten is negative.
  $0.0029 = 2.9 \times 10^{-3}$
Answer
$2.9 \times 10^{-3}$
3Multiplying two numbers in standard form
Building confidence• multiplication, index laws
Question
Work out $(4 \times 10^5) \times (3 \times 10^7)$ , giving your answer in standard form.
Step-by-step solution
1. Step 1
  Multiply the coefficients.
  $4 \times 3 = 12$
2. Step 2
  Add the powers of ten.
  $10^5 \times 10^7 = 10^{12}$
3. Step 3
  Tidy: $12$ is not between $1$ and $10$ , so write it as $1.2 \times 10^1$ and combine.
  $12 \times 10^{12} = 1.2 \times 10^{13}$
Answer
$1.2 \times 10^{13}$
4Dividing two numbers in standard form
Building confidence• division, index laws
Question
Work out $(6 \times 10^{-2}) \div (4 \times 10^3)$ , giving your answer in standard form.
Step-by-step solution
1. Step 1
  Divide the coefficients.
  $6 \div 4 = 1.5$
2. Step 2
  Subtract the powers of ten.
  $10^{-2} \div 10^{3} = 10^{-2-3} = 10^{-5}$
3. Step 3
  The coefficient is already between $1$ and $10$ , so write the answer straight away.
  $(6 \times 10^{-2}) \div (4 \times 10^3) = 1.5 \times 10^{-5}$
Answer
$1.5 \times 10^{-5}$
5Adding two numbers in standard form
Stretch• addition, matching powers
Question
Work out $5.4 \times 10^6 + 7.2 \times 10^5$ , giving your answer in standard form.
Step-by-step solution
1. Step 1
  Rewrite the smaller-power number so both share the same power of ten.
  $7.2 \times 10^5 = 0.72 \times 10^6$
2. Step 2
  Add the coefficients while the power of ten stays the same.
  $5.4 + 0.72 = 6.12$
3. Step 3
  Attach the shared power of ten. The coefficient is already between $1$ and $10$ , so no tidying needed.
  $5.4 \times 10^6 + 7.2 \times 10^5 = 6.12 \times 10^6$
Answer
$6.12 \times 10^6$

Key Definitions and Keywords — Standard Form

The important words for standard form and what they mean — learn these so you can explain your thinking clearly.

Standard form
Key word
A way of writing a number as $a \times 10^n$ , where $1 \le a < 10$ and $n$ is an integer. Also called scientific notation.
Coefficient
Key word
The $a$ part of a number in standard form — a value at least $1$ and less than $10$ .
Example
In $6.2 \times 10^5$ the coefficient is $6.2$ .
Power of ten
Key word
The $10^n$ part of a number in standard form. The exponent $n$ tells you how many places to slide the decimal point.
Exponent (index)
The small raised number that says how many times the base is multiplied by itself. In $10^4$ the exponent is $4$ .
Ordinary form
Key word
The everyday way of writing a number, without a power of ten — for example $0.0029$ or $63{,}000{,}000$ .
Scientific notation
Another name for standard form, used widely in science and on calculator displays.
Positive power of ten
A power of ten with a positive exponent, e.g. $10^3 = 1000$ . Used for numbers larger than $10$ .
Negative power of ten
Key word
A power of ten with a negative exponent, e.g. $10^{-3} = 0.001$ . Used for numbers smaller than $1$ .
Example
$3.5 \times 10^{-4} = 0.00035$ .
Index laws
The rules for combining powers with the same base. Two key ones: $10^m \times 10^n = 10^{m+n}$ and $10^m \div 10^n = 10^{m-n}$ .
Order of magnitude
The size of a number expressed as a power of ten. $4.2 \times 10^6$ has order of magnitude $10^6$ , so it is in the millions.
Decimal point
The point that separates the whole-number part of a number from its fractional part. In standard form it sits just after the first non-zero digit.
Tidying
Adjusting a number so its coefficient lies between $1$ and $10$ . Move the decimal point and change the power of ten by the same amount.

Common Mistakes and Misconceptions — Standard Form

The slip-ups students most often make with standard form — and simple ways to avoid them.

✕Leaving the coefficient outside the range $1 \le a < 10$ , e.g. writing $52{,}000 = 52 \times 10^3$ .
Why it happens
The decimal point is only moved part of the way before the answer is written down.
How to avoid it
Always slide the decimal point until there is exactly one non-zero digit in front of it. $52{,}000 = 5.2 \times 10^4$ .
✕Using a positive power for a small number or a negative power for a large one.
Why it happens
The sign is chosen from habit rather than from the size of the number.
How to avoid it
Check the size of the answer: bigger than $10$ → positive power, smaller than $1$ → negative power, between $1$ and $10$ → power of zero.
✕Adding the powers of ten when adding numbers, e.g. $4 \times 10^3 + 2 \times 10^3 = 6 \times 10^6$ .
Why it happens
The index law for multiplication is over-applied to addition.
How to avoid it
Powers only combine in multiplication and division. For addition, match the powers first and then add the coefficients only.
✕Stopping at $14 \times 10^5$ and calling it standard form.
Why it happens
After multiplying coefficients the answer is written down without a final check.
How to avoid it
Inspect the coefficient at the end. If it is outside $1 \le a < 10$ , slide the decimal point and balance the power: $14 \times 10^5 = 1.4 \times 10^6$ .
✕Getting the power one out, e.g. writing $0.0042 = 4.2 \times 10^{-2}$ .
Why it happens
Hops of the decimal point are counted starting from one rather than from zero, or the leading zero is included by accident.
How to avoid it
Count each move of the decimal point carefully. $0.0042$ needs three moves to reach $4.2$ , so the answer is $4.2 \times 10^{-3}$ .

Practice questions

Practice questions with step-by-step worked solutions. Try one before checking the method.

Practice quiz

Get a report showing which sub-topics you've nailed and which ones still need work.

Standard Form — frequently asked questions

The things students keep getting wrong in this sub-topic, answered.

Standard Form

Short Study Notes in the form of Slides

Short Study Notes — Standard Form

Detailed Notes

What you’ll learn

1Writing a large number in standard form

2Writing a small number in standard form

3Multiplying two numbers in standard form

4Dividing two numbers in standard form

5Adding two numbers in standard form

Standard form

Coefficient

Power of ten

Exponent (index)

Ordinary form

Scientific notation

Positive power of ten

Negative power of ten

Index laws

Order of magnitude

Decimal point

Tidying

✕Leaving the coefficient outside the range 1≤a<101 \le a < 101≤a<10, e.g. writing 52,000=52×10352{,}000 = 52 \times 10^352,000=52×103.

✕Using a positive power for a small number or a negative power for a large one.

✕Adding the powers of ten when adding numbers, e.g. 4×103+2×103=6×1064 \times 10^3 + 2 \times 10^3 = 6 \times 10^64×103+2×103=6×106.

✕Stopping at 14×10514 \times 10^514×105 and calling it standard form.

✕Getting the power one out, e.g. writing 0.0042=4.2×10−20.0042 = 4.2 \times 10^{-2}0.0042=4.2×10−2.

Practice questions

Practice quiz

Assess your understanding

Standard Form — frequently asked questions

✕Leaving the coefficient outside the range $1 \le a < 10$ , e.g. writing $52{,}000 = 52 \times 10^3$ .

✕Adding the powers of ten when adding numbers, e.g. $4 \times 10^3 + 2 \times 10^3 = 6 \times 10^6$ .

✕Stopping at $14 \times 10^5$ and calling it standard form.

✕Getting the power one out, e.g. writing $0.0042 = 4.2 \times 10^{-2}$ .