Launching your learning experience…
Detailed notes on Electricity for Cambridge International A Levels Physics, covering key concepts, explanations, examples, and exam-focused revision points.
Ohm's law, I-V curves, resistivity. Distinguish definition from law.
Mapped to the Cambridge International A Level 9702 syllabus (2025-2027).
Distinguish ohmic and non-ohmic.
Ohm's law. Current proportional to PD at constant temperature, for a conductor. V=IR
Definition. R=V/I always. (Even non-ohmic.)
I-V curves.
Cambridge tip. Sketch and label thresholds, asymptotes, directions.
See the full worked example for resistance and resistivity →
Material constant.
Formula. R=ρL/A.
Resistivity ρ is a MATERIAL property; depends on substance and temperature.
Typical values (Ωm).
Effect of temperature. Metals: ρ increases with T. Semiconductors: ρ DECREASES with T.
Example. Cu wire 1.5 m, A=5×10−7 m², R=0.051 Ω: ρ=RA/L=1.7×10−8 Ωm.
Cambridge tip. Mark scheme rewards SI units throughout.
See the full worked example for resistance and resistivity →
Verbatim phrases and definitions Cambridge mark schemes credit.
Resistance/resistivity on every Paper. Most-tested: Ohm's law (4-5 marks), I-V curves (6 marks), resistivity calc (6-7 marks).
Sources: Cambridge International A Level Physics 9702 syllabus (2025-2027); 9702 Examiner Reports 2022-2024; 9702/22 May/Jun 2024 question paper and mark scheme. Last reviewed 2026-05-11.
Step-by-step solutions to past-paper-style questions on resistance and resistivity, written exactly the way a tutor would explain them at the board.
Question
A 12 V battery drives 0.40 A through a resistor. Find the resistance. (4 marks)
Step-by-step solution
Step 1
R=V/I.
R=12/0.40=30 Ω
Answer
R=30 Ω.
Question
A copper wire 1.5 m long with cross-section 5.0×10−7 m² has resistance 0.051 Ω. Find the resistivity. (6 marks)
Step-by-step solution
Step 1
R=ρL/A⇒ρ=RA/L.
ρ=1.5(0.051)(5.0×10−7)≈1.7×10−8 Ωm
Answer
ρ≈1.7×10−8 Ωm.
Question
Describe I-V characteristics for (a) ohmic resistor, (b) filament lamp, (c) semiconductor diode. (6 marks)
Step-by-step solution
Step 1
(a) Ohmic. Straight line through origin. Slope = 1/R.
Step 2
(b) Filament lamp. Curve through origin. Resistance INCREASES with temperature (current heats filament).
Step 3
(c) Semiconductor diode. Zero current until threshold (~0.7 V); then current rises rapidly. Reverse: ~zero current.
Answer
(a) Straight line. (b) Curve up — R increases. (c) Threshold then steep rise; one-way.
The formulae you need to memorise for resistance and resistivity on the Cambridge International A Level 9702 paper, with every variable defined in plain English and a note on when to use it.
V=IR
When to use
For ohmic devices at constant temperature.
R=AρL
When to use
Resistance from material property and dimensions.
Definitions to memorise and the exact keywords mark schemes credit for resistance and resistivity answers — sharpened from recent examiner reports for the 2026 Cambridge International A Level 9702 sitting.
Ratio of PD to current. R=V/I. Units: ohm (Ω) = V/A.
Current proportional to PD at constant temperature, for a conductor.
Material property. ρ=RA/L. Units: Ω·m.
The traps other students keep falling into on resistance and resistivity questions — taken from recent Cambridge International A Level 9702 examiner reports and mark schemes — and how to avoid them.
9702 Examiner Reports 2022-2024
Why it happens
Confusing definition with law.
How to avoid it
R=V/I is a DEFINITION of resistance (always works). Ohm's LAW requires I∝V at constant T — a relationship that holds for ohmic devices only.
The things students keep getting wrong in this sub-topic, answered.