Key result. If X∼N(μ1,σ12) and Y∼N(μ2,σ22) are INDEPENDENT, then
aX+bY∼N(aμ1+bμ2,a2σ12+b2σ22).
Special cases.
- X+Y∼N(μ1+μ2,σ12+σ22).
- X−Y∼N(μ1−μ2,σ12+σ22).
Example. X∼N(50,16), Y∼N(40,9).
- X−Y∼N(10,25).
Sample mean. If X1,…,Xn are iid N(μ,σ2):
Xˉ∼N(μ,σ2/n).
Cambridge tip. Always state independence and that normals are involved.