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Detailed notes on Statistics for Cambridge IGCSE Mathematics, covering key concepts, explanations, examples, and exam-focused revision points.
Display and interpret data with the right chart for the data type. Cambridge tests construction (drawing) AND interpretation (reading values, comparing). Histograms are special — frequency DENSITY, not frequency.
Mapped to the Cambridge IGCSE 0580 syllabus (2025-2027).
Bars of equal width, separated by gaps. Height = frequency. For DISCRETE or categorical data.
Use for. Discrete or categorical data — number of pets, favourite subject, day of the week.
Rules.
Multi-bar charts. For comparing two categories side-by-side (e.g. boys' vs girls' favourite subjects), draw paired bars with a key.
Worked. Survey of 50 students' favourite sport: football 20, tennis 15, cricket 10, swimming 5.
Angle of each sector =totalfrequency×360°.
Use for. Showing how a whole is split into proportions.
Construction.
Worked. Same survey: football 20, tennis 15, cricket 10, swimming 5. Total 50.
Reading a pie chart. If you know the total and the angle, the frequency is 360θ×total.
Cambridge tip. Mark schemes credit a clear angle calculation table — even if the drawing is rough.
A symbol represents a fixed number of items. Key required.
Use for. Visually appealing, easy-to-grasp summaries — especially when numbers are small or for younger audiences.
Rules.
Worked. Pictogram of class books read this term, where each book symbol =4 books:
Reading. Multiply the number of full symbols (plus fractions) by the key value.
Cambridge tip. Always SHOW the key — Cambridge mark schemes deduct for missing keys.
Bar AREA = frequency. Use FREQUENCY DENSITY (f/ class width) when class widths are unequal.
Use for. Continuous data, especially with UNEQUAL class widths.
Key formula. frequency density=class widthfrequency.
The HEIGHT of each bar is frequency density. The AREA of each bar (= height × width) equals the frequency.
Why? With unequal class widths, plotting frequency directly would mislead — a wide-class bar would look more important than it is. Frequency density corrects for the width.
Worked. Times to complete a task (minutes):
| Class | Frequency f | Width | Frequency density |
|---|---|---|---|
| 0<t≤10 | 8 | 10 | 0.8 |
| 10<t≤20 | 14 | 10 | 1.4 |
| 20<t≤40 | 16 | 20 | 0.8 |
| 40<t≤60 | 12 | 20 | 0.6 |
Reading a histogram. The frequency in any class equals (height × width). To find the number of values in a partial class (e.g. 15<t≤25), compute the area of the relevant rectangle slice.
No gaps. Bars in a histogram TOUCH (because data is continuous). Bar charts have gaps; histograms don't.
Discrete + categories: bar. Proportions of a whole: pie. Continuous: histogram. Visual / informal: pictogram.
| Data type | Best chart |
|---|---|
| Discrete or categorical | Bar chart |
| Showing proportions of a whole | Pie chart |
| Continuous, equal class widths | Histogram (or frequency polygon) |
| Continuous, unequal class widths | Histogram with frequency density |
| Informal / friendly | Pictogram |
| Compare a few small numbers | Bar chart |
Cambridge questions. Often ask "what type of chart is most suitable" — answer with the data TYPE (discrete vs continuous, equal vs unequal widths) as the justification.
Verbatim phrases and definitions Cambridge mark schemes credit.
Statistical charts appear most years — Paper 2 (3-5 marks: read or construct a simple chart) and Paper 4 (5-7 marks: histogram with frequency density and unequal widths). Examiner reports flag two errors: (i) plotting frequency instead of frequency density on a histogram when widths are unequal, (ii) angles in a pie chart not summing to 360°.
Sources: Cambridge IGCSE Mathematics 0580 syllabus 2025-2027 (E11.8-11.9); 0580/42 Oct/Nov 2024 — Q18 (histogram, unequal widths); 0580 Examiner Reports 2022-2024. Last reviewed 2026-05-05.
Step-by-step solutions to past-paper-style questions on statistical charts and diagrams, written exactly the way a tutor would explain them at the board.
Almost every statistical charts and diagrams exam question is one of these shapes. Learn to spot each one and you will always know how to start.
Recognise it by
The whole question is built around a chart — construct a pie chart, draw a histogram / frequency polygon, or read / compare a bar chart or box-and-whisker plot.
How to approach it
Match the chart's rule: pie sector =totalfreq×360°; histogram height = frequency density class widthfreq for unequal classes; frequency polygon points plotted at class midpoints; box plot read directly for median, range and IQR.
Common trap
Examiner reports flag putting frequency (not frequency density) on a histogram with unequal classes, plotting frequency polygons against a class boundary instead of the midpoint, drawing gaps between histogram bars, and reading the box plot's middle line as the mean rather than the median.
Question
30 students chose a sport: football 12, tennis 9, hockey 6, swimming 3. Find the angle for each sector.
Step-by-step solution
Step 1
Each frequency → angle =totalfreq×360°.
Step 2
Compute.
F:3012×360=144°; T:108°; H:72°; S:36°
Answer
144°,108°,72°,36°
Question
Frequency table: [0,10)=8, [10,25)=18, [25,30)=7. Find the frequency densities.
Step-by-step solution
Step 1
FD=class widthfrequency.
Step 2
Compute each.
108=0.8; 1518=1.2; 57=1.4
Answer
FDs: 0.8, 1.2, 1.4.
Examiner tip
Histogram bars use frequency DENSITY on the y-axis (not frequency) when class widths are unequal.
Question
A box plot shows: min 4, Q1=7, median 10, Q3=14, max 20. State the median, range, and IQR.
Step-by-step solution
Step 1
Direct reads.
median=10, range=20−4=16, IQR=14−7=7
Answer
Median 10, range 16, IQR 7.
Question
Compare the heights of pupils in two classes shown by two bar charts.
Step-by-step solution
Step 1
Compare modal classes, ranges, or central tendency.
Answer
Use direct reads from the charts to comment on most-common heights and spread.
Question
A bar chart shows the number of books read by 25 students last month: 0 books →4, 1 book →8, 2 books →7, 3 books →4, 4 books →2. State the modal number of books and the total number of books read.
Step-by-step solution
Step 1
Modal = bar with greatest frequency. Highest bar is at 1 book (8 students).
Step 2
Total books = ∑fx.
0(4)+1(8)+2(7)+3(4)+4(2)=0+8+14+12+8=42
Answer
Mode =1 book; total =42 books read.
Question
A dual bar chart shows favourite drinks for 30 boys and 30 girls. Boys: tea 5, coffee 10, juice 15. Girls: tea 12, coffee 6, juice 12. State which drink shows the biggest difference between boys and girls, and give that difference.
Step-by-step solution
Step 1
Compute each pairwise difference: tea ∣12−5∣=7, coffee ∣10−6∣=4, juice ∣15−12∣=3.
Step 2
Biggest difference is for tea.
Answer
Tea, with a difference of 7 students.
Question
Frequency table of test marks: [0,10)=3, [10,20)=8, [20,30)=12, [30,40)=5. Describe the points you would plot on a frequency polygon.
Step-by-step solution
Step 1
Plot frequency against the MIDPOINT of each class.
Step 2
Midpoints: 5,15,25,35. Points: (5,3), (15,8), (25,12), (35,5).
Step 3
Join the points with straight line segments.
Answer
Plot (5,3),(15,8),(25,12),(35,5) and join with straight lines.
Examiner tip
The examiner report flags candidates who plot against the lower (or upper) class boundary instead of the midpoint, losing the accuracy mark.
Question
Frequency table: [0,5)=4, [5,10)=9, [10,15)=12, [15,20)=7, [20,25)=3. Each class has width 5. State the heights of the histogram bars if (a) frequency is on the y-axis, (b) frequency density is on the y-axis.
Step-by-step solution
Step 1
(a) With equal class widths, frequency on the y-axis is acceptable. Heights: 4,9,12,7,3.
Step 2
(b) Frequency density =class widthfrequency. Divide each by 5.
FD: 0.8,1.8,2.4,1.4,0.6
Answer
(a) Heights =4,9,12,7,3. (b) FDs =0.8,1.8,2.4,1.4,0.6.
Question
A histogram has class [0,20) with frequency density 0.6, class [20,30) with FD 1.5, class [30,60) with FD 0.4. Find (a) the frequency in each class, and (b) the total number of data points.
Step-by-step solution
Step 1
Frequency =FD×class width.
Step 2
Class [0,20): width 20.
f=0.6×20=12
Step 3
Class [20,30): width 10.
f=1.5×10=15
Step 4
Class [30,60): width 30.
f=0.4×30=12
Step 5
Total.
12+15+12=39
Answer
(a) 12, 15, 12. (b) 39 data points.
Examiner tip
This is a classic A* trap. The examiner report consistently flags students who multiply by '1' (treating FD as frequency) or who use the wrong class width. AREA of the bar = frequency.
The formulae you need to memorise for statistical charts and diagrams on the Cambridge IGCSE 0580 paper, with every variable defined in plain English and a note on when to use it.
angle=totalfrequency×360°
When to use
Constructing a pie chart.
FD=class widthfrequency
When to use
Histograms with unequal class widths.
frequency=FD×class width
When to use
Reading a frequency from a histogram bar.
Definitions to memorise and the exact keywords mark schemes credit for statistical charts and diagrams answers — sharpened from recent examiner reports for the 2026 0580 sitting.
A bar-style chart for continuous data. With unequal class widths, the y-axis is frequency density and the AREA equals frequency.
Frequency divided by class width. Standardises bars so that AREA represents frequency.
A circular chart split into sectors proportional to frequency.
A summary diagram showing min, Q1, median, Q3, max.
The traps other students keep falling into on statistical charts and diagrams questions — taken from recent Cambridge IGCSE 0580 examiner reports and mark schemes — and how to avoid them.
0580/42 — every series
Why it happens
Forgetting to convert to frequency density.
How to avoid it
Unequal classes → ALWAYS use frequency DENSITY. Bar AREA = frequency.
Why it happens
Rounding errors.
How to avoid it
Check the four (or however many) sectors sum to exactly 360°. Adjust the largest by the rounding error if needed.
Why it happens
Drawing it like a bar chart.
How to avoid it
Histograms have NO gaps — continuous data, bars touch.
Why it happens
Confusing mean and median.
How to avoid it
Box plot middle line = MEDIAN, not mean.
The things students keep getting wrong in this sub-topic, answered.