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Detailed notes on Number for Cambridge IGCSE Mathematics, covering key concepts, explanations, examples, and exam-focused revision points.
Adding, subtracting, multiplying and dividing positive and negative numbers. The arithmetic is straightforward; the sign rules cause more lost marks on Paper 2 than any other topic in Number.
Mapped to the Cambridge IGCSE 0580 syllabus (2025-2027).
Picture every operation as a movement on a number line. Right for positive, left for negative.
Imagine standing on the number line at the first number. The operation tells you which way and how far to move.
Adding a positive = move RIGHT. Adding a negative = move LEFT. Subtracting a positive = move LEFT. Subtracting a negative = move RIGHT (it's a "double negative").
Worked walkthroughs:
The sign-rewrite trick. Two adjacent signs combine: +(−)=−,−(−)=+,−(+)=−,+(+)=+. So 5−(−2)=5+2=7 and 5+(−2)=5−2=3.
Same sign → positive. Different signs → negative. The rule applies to both multiplication and division.
The sign of a product depends only on the signs of the factors:
| First sign | Second sign | Product/quotient |
|---|---|---|
| + | + | + |
| − | − | + |
| + | − | − |
| − | + | − |
So
For products of more than two numbers, count the number of negatives:
So (−2)(−3)(−4)(−5)=120 (four negatives → positive) and (−2)(−3)(−4)=−24 (three negatives → negative).
Brackets and indices first. The fastest way to lose marks is forgetting whether a square attaches to the negative.
The order of operations (BIDMAS / PEMDAS / BODMAS — same idea) is unchanged when negatives appear:
The trap: how does a square attach to a negative?
These are different by sign! Always check whether the negative sits inside brackets.
Worked example. 7−(−2)3÷4×2.
Cambridge loves dressing directed-number questions in temperature, finance, or sea-level clothing.
Most directed-number questions on the IGCSE wrap the arithmetic in a real-world story. Recognise the cue and the rest is mechanical.
Temperature. "The temperature is −7°C at 6am and rises by 12°C by midday." → −7+12=5°C.
Bank balance / debt. "An account is $45 overdrawn (i.e. balance −45). The account holder pays in $60." → −45+60=15. New balance $15.
Altitude. "A submarine is 300m below sea level. It rises 120m." → −300+120=−180m. Still 180m below.
Difference between two values. "Find the difference between 5°C and −12°C." → 5−(−12)=17°C. Subtract the smaller from the larger.
When questions ask "how much hotter / higher / further", expect a positive answer. The sign trick is to set up the calculation as (later/larger) − (earlier/smaller).
Verbatim phrases and definitions Cambridge mark schemes credit.
Directed numbers usually appear in 1-mark questions on Paper 2 (calculator) — a quick sign-rule check inside a longer problem. Paper 4 questions hide them inside word problems, often asking for a difference between two signed quantities. Examiner reports flag (−3)2 vs −32 confusion every series — and the slip-up is almost always punished, even on follow-on parts.
Sources: Cambridge IGCSE Mathematics 0580 syllabus 2025-2027 (E1.7); 0580/22 May/Jun 2024 — Q2 (signed-number arithmetic); 0580 Examiner Reports 2022-2024. Last reviewed 2026-05-05.
Step-by-step solutions to past-paper-style questions on directed numbers, written exactly the way a tutor would explain them at the board.
Almost every directed numbers exam question is one of these shapes. Learn to spot each one and you will always know how to start.
Recognise it by
A bare instruction — calculate, evaluate — applied to a signed expression: double signs, sign rules for × and ÷, powers of negatives, or a BIDMAS chain.
How to approach it
Rewrite every double sign as a single sign first (−(−a)=+a), then apply BIDMAS, counting the negatives in products — an odd count gives a negative result, an even count positive.
Common trap
Examiner reports flag −32 versus (−3)2 — without brackets the power applies only to 3, so −32=−9 but (−3)2=9.
Recognise it by
A real-world context — temperatures, bank balances, sea level — where quantities below a reference point are negative.
How to approach it
Translate each rise/fall or deposit/payment into a signed addition, working through the events in order. For a 'difference' between extremes, compute high−low.
Common trap
Examiner reports flag the difference between temperatures written as a negative — distance is always positive, so use ∣high−low∣ or subtract the lower from the higher.
Recognise it by
Several pieces of information are chained together — a starting balance, revenue, costs and then conditional interest.
How to approach it
Work through each stage in sequence, carrying the running signed total, and decide the sign of every adjustment from the context (interest on a debt makes it more negative).
Common trap
Examiner reports flag candidates giving interest on a debt as a positive amount, which wrongly reduces the debt — track the sign of each step.
Question
Calculate (a) −7+(−4), (b) −3−(−9), (c) 5+(−12).
Step-by-step solution
Step 1
(a) Adding a negative is the same as subtracting: −7+(−4)=−7−4=−11.
Step 2
(b) Subtracting a negative is the same as adding: −3−(−9)=−3+9=6.
Step 3
(c) Add a negative — net result is subtraction: 5+(−12)=5−12=−7.
Answer
(a) −11 (b) 6 (c) −7
Examiner tip
Always rewrite double signs (+− or −−) as a single sign before evaluating. Most arithmetic slips happen here.
Question
Evaluate (a) (−6)×(−4), (b) 8−72, (c) (−3)2, (d) −32.
Step-by-step solution
Step 1
(a) Negative times negative is positive: (−6)×(−4)=24.
Step 2
(b) Negative divided by positive is negative: 8−72=−9.
Step 3
(c) The bracket means the whole −3 is squared: (−3)2=(−3)(−3)=9.
Step 4
(d) No bracket — the exponent applies only to 3, then negate: −32=−(32)=−9.
Answer
(a) 24 (b) −9 (c) 9 (d) −9
Examiner tip
Parts (c) and (d) are a classic distinction students miss — write the brackets clearly to avoid losing accuracy marks.
Question
The temperature at 6 a.m. was −4∘C. By midday it had risen by 11∘C. By 9 p.m. it had fallen by 13∘C from midday. Find the temperature at 9 p.m.
Step-by-step solution
Step 1
Midday: −4+11=7∘C.
Step 2
9 p.m.: 7−13=−6∘C.
Answer
−6∘C
Question
Asha's bank balance is −45 dollars (i.e. $45 overdrawn). She deposits $120 and then pays a bill of $60. What is her new balance?
Step-by-step solution
Step 1
Start: −45. Deposit: −45+120=75.
Step 2
Pay bill: 75−60=15.
Answer
$15
Question
Calculate (a) −8+(−3)−(−11), (b) −(−5)+(−4)−(+7), (c) 12−(−6)+(−9).
Step-by-step solution
Step 1
(a) Rewrite double signs: −8−3+11=−11+11=0.
−8+(−3)−(−11)=−8−3+11=0
Step 2
(b) Rewrite: −(−5)=+5, +(−4)=−4, −(+7)=−7. So 5−4−7=−6.
−(−5)+(−4)−(+7)=5−4−7=−6
Step 3
(c) Rewrite: 12−(−6)=12+6=18; then 18+(−9)=18−9=9.
12−(−6)+(−9)=12+6−9=9
Answer
(a) 0 (b) −6 (c) 9
Examiner tip
Mark schemes award method marks for explicit double-sign simplification on the working line. Skip that step and one arithmetic slip kills the whole question.
Question
Calculate (a) (−2)×(−3)×(−5), (b) (−1)7, (c) (−4)×(−2)×(−3)×(−5).
Step-by-step solution
Step 1
Count the negatives. Odd count → negative result; even count → positive result.
Step 2
(a) Three negatives (odd): magnitude 2×3×5=30, sign negative. Result −30.
Step 3
(b) (−1)7 is (−1) multiplied by itself 7 times — seven negatives, odd: −1.
Step 4
(c) Four negatives (even): magnitude 4×2×3×5=120, sign positive. Result +120.
Answer
(a) −30 (b) −1 (c) 120
Examiner tip
The examiner report flags that candidates often apply 'two negatives make a positive' twice and forget the third. Count the negatives once at the end — the rule is parity.
Question
Evaluate −89−43, giving your answer as a fraction in lowest terms.
Step-by-step solution
Step 1
Dividing by a fraction is the same as multiplying by its reciprocal.
−89−43=−43×−98
Step 2
Sign rule: negative × negative = positive.
=+4×93×8=3624
Step 3
Simplify by dividing top and bottom by gcd(24,36)=12.
=32
Answer
32
Examiner tip
Cancel before multiplying where possible — Cambridge mark schemes accept either order but candidates who multiply first more frequently produce arithmetic errors.
Question
At 06{:}00 the temperatures in five cities were −12∘C, −3∘C, +7∘C, −8∘C and +4∘C. Find (a) the difference between the highest and lowest temperatures, (b) the mean temperature.
Step-by-step solution
Step 1
(a) Identify the extremes: highest =+7∘C, lowest =−12∘C. Difference =7−(−12)=7+12=19∘C.
7−(−12)=19
Step 2
(b) Sum the five values: −12+(−3)+7+(−8)+4=−12−3+7−8+4=−12.
Step 3
Divide by the count: mean =5−12=−2.4∘C.
mean=5−12=−2.4
Answer
(a) 19∘C (b) −2.4∘C
Examiner tip
Examiner reports show many candidates write the difference as −19. Distance between two temperatures is always positive — use ∣high−low∣ or take the larger value first.
Question
Without a calculator, evaluate −7+(−2)3(−3)2−2×(−4).
Step-by-step solution
Step 1
Apply BIDMAS. Start with brackets/indices in the numerator: (−3)2=9.
Step 2
Multiplication: 2×(−4)=−8. So numerator =9−(−8)=9+8=17.
(−3)2−2×(−4)=9+8=17
Step 3
Denominator: (−2)3=−8. So denominator =−7+(−8)=−15.
−7+(−2)3=−7−8=−15
Step 4
Divide.
−1517=−1517
Answer
−1517 (or −1152).
Examiner tip
The 2024 examiner report notes candidates often compute −32 as −9 inside the bracket, losing the indices step. With brackets, (−3)2=9 — square the negative.
Question
On 1 March a small business has a balance of -\1,200 (i.e. \1,200 in debt). During March it earns $3,450 in revenue and incurs costs of $2,860. On 1 April the bank applies 2% interest on the new positive balance (or charges 5% on a negative one). Find the balance on 2 April.
Step-by-step solution
Step 1
Compute the balance after March: −1200+3450−2860.
−1200+3450−2860=−610
Step 2
The balance is still negative (-\610),sothebankcharges5%$ interest on the debt.
interest=−610×0.05=−30.50
Step 3
Apply the interest. Charging interest increases the debt — add the (negative) interest to the (negative) balance.
new balance=−610+(−30.50)=−640.50
Answer
-\640.50 (i.e. \640.50 in debt).
Examiner tip
Mark schemes award method marks for the correct sign of each step. Candidates who write the interest as +\30.50$ (and so reduce the debt) lose two accuracy marks — interest charged on a debt makes the debt worse.
The formulae you need to memorise for directed numbers on the Cambridge IGCSE 0580 paper, with every variable defined in plain English and a note on when to use it.
(+)⋅(+)=(+), (−)⋅(−)=(+), (+)⋅(−)=(−), (−)⋅(+)=(−)
When to use
Whenever you multiply or divide two signed numbers.
+(−a)=−a,−(−a)=+a
When to use
Use to simplify expressions before adding or subtracting.
Definitions to memorise and the exact keywords mark schemes credit for directed numbers answers — sharpened from recent examiner reports for the 2026 0580 sitting.
A number with a direction (sign) — positive (above zero) or negative (below zero).
A number greater than zero. Sometimes written with a leading +.
A number less than zero, written with a leading −.
The size of a number ignoring its sign. ∣−7∣=7.
The number that, when added to a given number, gives zero. The opposite of 5 is −5.
The traps other students keep falling into on directed numbers questions — taken from recent Cambridge IGCSE 0580 examiner reports and mark schemes — and how to avoid them.
0580/12 — recurring across recent series
Why it happens
3−(−2) looks confusing under pressure, leading to 1 instead of 5.
How to avoid it
Always rewrite as 3+2=5 before evaluating.
0580/22 examiner report
Why it happens
Without the bracket, the negative is not squared, but students often square it anyway.
How to avoid it
Read the brackets carefully: (−3)2=9, −32=−9.
Why it happens
Treating subtraction as commutative.
How to avoid it
Use a number line: 5−12 → start at 5, move 12 left → −7.
Why it happens
Students apply "two negatives make a positive" then forget the third.
How to avoid it
Count the negatives: odd count → negative; even count → positive.
The things students keep getting wrong in this sub-topic, answered.