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Detailed notes on Properties of Waves, including Light and Sound for Cambridge IGCSE Coordinated Science, covering key concepts, explanations, examples, and exam-focused revision points.
Sound is a longitudinal mechanical wave that requires a medium. Cambridge tests wave properties of sound (frequency = pitch, amplitude = loudness), the speed of sound in different media, echoes, and ultrasound applications.
Mapped to the Cambridge IGCSE 0654 syllabus (2025-2027).
Sound travels as compressions and rarefactions; cannot travel through vacuum.
Nature of sound:
Evidence: Bell jar experiment: bell rings inside evacuated jar → sound fades as air is removed → silence in vacuum.
Speed of sound in different media:
| Medium | Speed |
|---|---|
| Air (20°C) | ≈ 330–340 m/s |
| Water | ≈ 1500 m/s |
| Steel | ≈ 5000 m/s |
Sound travels faster in denser/more rigid media (particles closer → vibrations transmitted more quickly).
Pitch and loudness:
Human hearing range: 20 Hz – 20 000 Hz (20 kHz)
Oscilloscope display:
Reflected sound (echo) is used to measure distance; ultrasound has medical and industrial uses.
Echoes:
distance = (speed × time) / 2 OR: speed = 2 × distance / time
Example: A ship sends a sonar pulse that returns after 0.4 s. Speed of sound in water = 1500 m/s. Find depth.
d = (1500 × 0.4) / 2 = 300 m
Ultrasound (f > 20 000 Hz):
Medical uses:
Industrial uses:
Why ultrasound is preferred over X-rays for foetal imaging:
Verbatim phrases and definitions Cambridge mark schemes credit.
Paper 4: 'A bat emits an ultrasound pulse that reflects from a wall and returns after 0.02 s. Speed of sound = 340 m/s. Calculate the distance to the wall' (2 marks — d = 340 × 0.02/2 = 3.4 m). 'State TWO uses of ultrasound in medicine' (2 marks — foetal scanning; kidney stone detection). 'Explain why sound cannot travel through a vacuum' (2 marks — sound needs particles to transmit vibrations; vacuum has no particles). Oscilloscope: 'Describe how the trace would change if the note becomes louder but the same pitch' (2 marks — greater amplitude; same frequency/number of waves).
Sources: Cambridge IGCSE Coordinated Sciences 0654 syllabus 2025-2027 (P4); 0654 Examiner Reports 2022-2024. Last reviewed 2026-05-14.
Step-by-step solutions to past-paper-style questions on sound, written exactly the way a tutor would explain them at the board.
Question
A ship sends out a sound pulse and receives the echo from the seabed after 0.40s. The speed of sound in sea water is 1500m/s. Calculate the depth of the seabed.
Step-by-step solution
Step 1
The pulse travels to the seabed and back, so the distance to the seabed = total distance / 2.
Total distance=v×t=1500×0.40=600m
Step 2
Depth = total distance / 2.
d=2600=300m
Answer
Depth =300m
Examiner tip
The time given is the round-trip time. Always divide by 2 for the one-way distance.
Question
Two musical notes are played. Note A has a higher frequency than note B. Note B is louder than note A. Sketch the waveforms for both notes on the same time axis and compare their pitch and loudness.
Step-by-step solution
Step 1
Note A: higher frequency → more cycles per second → waves closer together on the time axis (shorter period). Lower amplitude → smaller peak-to-trough distance.
Step 2
Note B: lower frequency → waves further apart on the time axis. Higher amplitude → larger peak-to-trough distance.
Step 3
Pitch: Note A is higher pitched (higher frequency). Loudness: Note B is louder (larger amplitude).
Answer
A: high frequency (closely spaced waves), small amplitude. B: low frequency (widely spaced waves), large amplitude. A is higher pitched; B is louder.
Question
Explain how ultrasound is used to produce an image of a foetus. Include the meaning of 'ultrasound' and why it is preferred over X-rays for this purpose.
Step-by-step solution
Step 1
Ultrasound is sound with a frequency above the upper limit of human hearing, >20000Hz.
Step 2
A transducer (probe) emits pulses of ultrasound directed into the body. At each boundary between tissues of different densities (e.g., tissue/bone, tissue/fluid), some of the pulse is reflected as an echo.
Step 3
The time between emission and reception of each echo is measured. Using d=vt/2 with the known speed of ultrasound in tissue, the depth of each boundary is calculated. A computer uses these data to construct a 2D image.
Step 4
Advantage over X-rays: ultrasound is non-ionising — it does not damage DNA or increase cancer risk. X-rays are ionising and could harm the developing foetus.
Answer
Ultrasound (>20000Hz) pulses reflect at tissue boundaries; echo timing gives depth. Preferred over X-rays because it is non-ionising and safer for the foetus.
The formulae you need to memorise for sound on the Cambridge IGCSE 0654 paper, with every variable defined in plain English and a note on when to use it.
d=2v×t
When to use
Finding the depth or distance of a reflecting surface from an echo time.
v=fλ
When to use
Relating the speed, frequency, and wavelength of a sound wave.
Definitions to memorise and the exact keywords mark schemes credit for sound answers — sharpened from recent examiner reports for the 2026 0654 sitting.
A wave in which the oscillations of particles are parallel to the direction of energy transfer. Sound is a longitudinal wave consisting of alternating compressions and rarefactions.
A region in a longitudinal wave where particles are closer together than normal, producing a region of higher pressure.
Related: rarefaction
A region in a longitudinal wave where particles are further apart than normal, producing a region of lower pressure.
Related: compression
Sound with a frequency above the upper limit of human hearing (>20000Hz or 20kHz). Used in medical imaging, sonar, and cleaning.
The traps other students keep falling into on sound questions — taken from recent Cambridge IGCSE 0654 examiner reports and mark schemes — and how to avoid them.
Why it happens
Students confuse sound with light or EM waves.
How to avoid it
Sound is a mechanical wave requiring a medium (particles) to transmit energy. It cannot travel through a vacuum. This is why space is silent.
Why it happens
Students use d=vt with the full echo time, giving double the actual distance.
How to avoid it
Write d=vt/2 from the start. The sound travels to the reflector AND back — the distance is only half the total path.
Why it happens
Both describe how a sound 'sounds' and students mix the terms.
How to avoid it
Pitch = frequency. Loudness = amplitude (or intensity). A high-pitched sound can be quiet; a low-pitched sound can be loud.
The things students keep getting wrong in this sub-topic, answered.