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Detailed notes on Inheritance for Cambridge IGCSE Coordinated Science, covering key concepts, explanations, examples, and exam-focused revision points.
Monohybrid crosses track one gene at a time using Punnett squares. Cambridge tests crosses for dominant/recessive traits, codominance, and sex-linked conditions. Always show gametes and full Punnett squares.
Mapped to the Cambridge IGCSE 0654 syllabus (2025-2027).
A Punnett square shows all possible genotype combinations from a cross. It predicts probabilities, not certainties.
How to draw a Punnett square:
Example — Monohybrid cross: Tall (Bb) × Tall (Bb)
T = tall (dominant); t = short (recessive)
Gametes of parent 1: T, t Gametes of parent 2: T, t
| T | t | |
|---|---|---|
| T | TT | Tt |
| t | Tt | tt |
Genotype ratio: 1 TT : 2 Tt : 1 tt Phenotype ratio: 3 tall : 1 short
Test cross: To determine if a dominant phenotype individual is homozygous (TT) or heterozygous (Tt), cross with a homozygous recessive (tt).
When both alleles are expressed equally in the phenotype — neither is dominant over the other.
Codominance: when both alleles of a gene are expressed simultaneously in the phenotype of a heterozygote — neither masks the other.
ABO Blood Groups (human example):
| Genotype | Blood group (phenotype) |
|---|---|
| IAIA or IAIO | A |
| IBIB or IBIO | B |
| IAIB | AB (both antigens expressed — codominance) |
| IOIO | O |
Another example: Snapdragon flower colour
Notation for codominant alleles: Both written as superscripts of the same letter (IA, IB, IO for blood groups; CR, CW for flowers).
Sex is determined by the sex chromosomes: XX = female, XY = male. The Y chromosome from sperm determines the sex of the offspring.
Humans have 23 pairs of chromosomes:
Sex determination cross:
Father: XY (gametes: X or Y) Mother: XX (gametes: X only)
| X | Y | |
|---|---|---|
| X | XX (female) | XY (male) |
| X | XX (female) | XY (male) |
Result: 50% XX (female) : 50% XY (male) — in every pregnancy, 50% chance of each sex.
The sperm determines sex: Eggs always carry X. Sperm carry either X or Y. Which sperm fertilises the egg determines the sex.
Genes on the X chromosome are sex-linked. Males (XY) with one copy of a recessive X-linked allele will show the condition — they have no second X to mask it.
Sex-linked genes: genes located on the X chromosome (very few on Y). Since males have only ONE X chromosome, any allele on that X will be expressed — even if recessive.
Colour blindness (red-green) — recessive, X-linked:
Cross: Carrier female × Normal male: Mother: XCXc × Father: XCY
| XC | Y | |
|---|---|---|
| XC | XCXC (normal female) | XCY (normal male) |
| Xc | XCXc (carrier female) | XcY (colour blind male) |
Phenotype ratio: 25% normal female : 25% carrier female : 25% normal male : 25% colour blind male
Key features of X-linked recessive inheritance:
Verbatim phrases and definitions Cambridge mark schemes credit.
Paper 4: Always requires a complete Punnett square — write out gametes, draw the grid, fill in all four boxes, state genotype AND phenotype ratios. 'Explain why haemophilia is more common in males' (3 marks — X-linked, one allele expressed, males have no second X to mask it). 'A man has blood group O and a woman has blood group AB. State the possible blood groups of their children and show your working' (requires Punnett square). Mark schemes require the Punnett square to be shown — answers without it lose marks even if correct.
Sources: Cambridge IGCSE Coordinated Sciences 0654 syllabus 2025-2027 (B22); 0654/42 May/Jun 2024 — Q11 (genetics crosses); 0654 Examiner Reports 2022-2024. Last reviewed 2026-05-14.
Step-by-step solutions to past-paper-style questions on monohybrid inheritance, written exactly the way a tutor would explain them at the board.
Question
Two tall pea plants (Tt) are crossed. Show, using a Punnett square, the expected ratio of tall to short plants in the offspring.
Step-by-step solution
Step 1
Set up the Punnett square. Parents: Tt × Tt. Gametes: T or t (from each parent).
TtTTTTttTttt
Step 2
Offspring genotypes: TT (1) : Tt (2) : tt (1). Since T is dominant, TT and Tt are tall; tt is short.
Step 3
Phenotype ratio: 3 tall : 1 short.
Answer
Expected ratio: 3 tall : 1 short (genotype ratio 1 TT : 2 Tt : 1 tt).
Question
A woman is a carrier for colour blindness (XNXb). Her husband has normal vision (XNY). Show the possible genotypes and phenotypes of their sons.
Step-by-step solution
Step 1
Sons inherit the Y chromosome from their father and either XN or Xb from their mother.
XNYXNXNXNXNYXbXNXbXbY
Step 2
Sons' possible genotypes: XNY (normal vision) or XbY (colour blind). Since males are hemizygous (only one X chromosome), a single Xb allele causes colour blindness.
Step 3
Expected: 50% of sons have normal vision; 50% of sons are colour blind.
Answer
Sons: XNY (normal vision) or XbY (colour blind). 50% probability of colour blindness in sons because males have only one X chromosome; a single Xb allele is expressed.
Question
A person has blood group AB. State their genotype and explain why this is an example of codominance.
Step-by-step solution
Step 1
The genotype of a blood group AB individual is IAIB.
Step 2
In codominance, neither allele is dominant over the other. Both IA and IB alleles are expressed simultaneously in the heterozygote.
Step 3
The person produces both type A and type B antigens on their red blood cells. Neither allele is masked — both phenotypes are expressed → this is codominance.
Answer
Genotype: IAIB. Codominance: neither allele is dominant; both IA and IB are fully expressed; the person shows both A and B characteristics (AB blood group).
Question
Explain why sex-linked conditions such as colour blindness are more common in males than females.
Step-by-step solution
Step 1
The gene for colour blindness is located on the X chromosome (X-linked). Males have only one X chromosome (XY) — they are hemizygous for X-linked genes.
Step 2
If a male inherits even a single recessive allele (Xb) on his only X chromosome, there is no second X chromosome to carry a dominant allele to mask it. The condition is expressed.
Step 3
Females (XX) need two copies of the recessive allele (XbXb) to show colour blindness. A female with one Xb is only a carrier — the normal XN allele masks the effect. This is statistically less likely.
Answer
Males have only one X chromosome (hemizygous); a single recessive X-linked allele (Xb) causes the condition. Females need two copies of the recessive allele to be affected; one copy makes them a carrier with normal vision. Hence colour blindness is more common in males.
Definitions to memorise and the exact keywords mark schemes credit for monohybrid inheritance answers — sharpened from recent examiner reports for the 2026 0654 sitting.
A genetic cross between two individuals for a single gene, showing the expected ratios of offspring genotypes and phenotypes using a Punnett square.
A situation in which both alleles of a gene are fully expressed in the phenotype of a heterozygote. Neither allele is dominant over the other.
Example
ABO blood groups: IAIB → blood group AB (both A and B antigens expressed).
A gene located on one of the sex chromosomes (usually the X chromosome). Sex-linked conditions such as colour blindness and haemophilia are more common in males.
A heterozygous individual who carries one copy of a recessive allele (including sex-linked recessive) but does not show the associated phenotype.
Having only one allele of a gene, as in males for X-linked genes (XY individuals have only one X chromosome and therefore one allele for each X-linked gene).
A grid used to predict the expected genotypic and phenotypic ratios of offspring from a genetic cross by systematically combining parental gametes.
The traps other students keep falling into on monohybrid inheritance questions — taken from recent Cambridge IGCSE 0654 examiner reports and mark schemes — and how to avoid them.
Why it happens
Students confuse expected probability ratios with certain outcomes.
How to avoid it
A 3:1 ratio is a probability based on large numbers of offspring. In a small sample (e.g. 4 offspring), any combination is possible. Always write 'expected ratio' not 'definite outcome'.
Why it happens
Both involve heterozygotes with intermediate-looking phenotypes in some cases.
How to avoid it
Codominance: both alleles fully expressed (e.g. AB blood group: both A and B antigens). Incomplete dominance: a blended intermediate phenotype (e.g. red × white = pink flowers). Different concepts.
Why it happens
Students know colour blindness is more common in males and incorrectly conclude daughters cannot be affected.
How to avoid it
Daughters CAN be colour blind if they are homozygous recessive (XbXb). This requires a colour-blind father (XbY) AND a carrier or colour-blind mother.
Why it happens
Students know A, B, AB, O blood groups but confuse the genetics of the i (O) allele.
How to avoid it
Alleles: IA (codominant), IB (codominant), i (recessive). Blood group O = genotype ii. Blood group A = IAIA or IAi. Blood group B = IBIB or IBi.
The things students keep getting wrong in this sub-topic, answered.