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Detailed notes on Chemical Reactions for Cambridge IGCSE Coordinated Science, covering key concepts, explanations, examples, and exam-focused revision points.
The rate of reaction depends on how frequently and energetically reactant particles collide. Cambridge tests collision theory, the four factors (concentration, temperature, surface area, catalyst), and how to measure and interpret rate data.
Mapped to the Cambridge IGCSE 0654 syllabus (2025-2027).
Rate can be measured by following how quickly a reactant is used up or a product is formed over time.
Rate of reaction: the change in the amount of reactant (or product) per unit time.
Rate = change in quantity / time taken
Methods of measuring rate:
| Method | Suitable for |
|---|---|
| Volume of gas collected (gas syringe or displacement of water) | Reactions producing gas (H₂, CO₂, O₂) |
| Mass loss (top-pan balance) | Reactions producing a gas that escapes (CO₂) |
| Change in colour/transmission (colorimeter) | Reactions with a colour change |
| Change in pH | Acid-consuming reactions |
| Turbidity (cloudiness) | Precipitation reactions (sulfur from thiosulfate + HCl) |
Interpreting rate graphs:
All factors are explained by collision theory: more frequent collisions with sufficient energy = faster rate.
Collision theory: For a reaction to occur, reactant particles must:
1. Concentration (or pressure for gases):
2. Temperature:
3. Surface area (particle size):
4. Catalyst:
Important: Rate only affects HOW QUICKLY the reaction reaches completion — NOT the final amount of product (yield) — unless a catalyst is so selective it changes the products.
Verbatim phrases and definitions Cambridge mark schemes credit.
Paper 4: 'Explain, using collision theory, how increasing temperature increases the rate of reaction' (3 marks — more kinetic energy, more frequent collisions AND more collisions with energy ≥ Ea, faster rate). Graph interpretation: 'Compare the rates in experiments A and B from the graph' (steeper gradient = faster rate; same final volume = same amount of product; reach endpoint sooner). Practical planning: 'Describe how you would investigate the effect of concentration on rate' (must identify variables, method of measurement, how to make it fair test). Catalyst explanation questions score well if they include: lower Ea, more particles react.
Sources: Cambridge IGCSE Coordinated Sciences 0654 syllabus 2025-2027 (C7); 0654 Examiner Reports 2022-2024. Last reviewed 2026-05-14.
Step-by-step solutions to past-paper-style questions on rate (speed) of reaction , written exactly the way a tutor would explain them at the board.
Question
A student collects 60cm3 of gas in 30s. Calculate the mean rate of reaction.
Step-by-step solution
Step 1
Apply the rate formula.
rate=timechange in quantity=3060=2cm3/s
Answer
Rate =2cm3/s
Examiner tip
Include units in the answer. Rate can also be expressed as change in mass per second (g/s) or change in concentration per second (mol/dm³/s).
Question
Explain, using collision theory, why increasing the concentration of a reactant in solution increases the rate of reaction.
Step-by-step solution
Step 1
Increasing the concentration means more reactant particles are present per unit volume.
Step 2
The greater number of particles per unit volume leads to more frequent collisions between reactant particles.
Step 3
More collisions per second with energy ≥ activation energy → more successful collisions → higher rate of reaction.
Answer
Higher concentration → more particles per dm³ → more frequent collisions → more successful collisions per second → faster rate.
Examiner tip
Three marking points: more particles per volume / more frequent collisions / more successful collisions (or more per second with energy ≥ Ea).
Question
Powdered calcium carbonate reacts faster with hydrochloric acid than marble chips of the same mass. Explain why, using collision theory.
Step-by-step solution
Step 1
Powdering the calcium carbonate breaks it into much smaller pieces, greatly increasing the total surface area exposed to the acid.
Step 2
More CaCO₃ particles are in contact with (exposed to) the acid molecules at the same time.
Step 3
More surface particles exposed → more frequent collisions between CaCO₃ and HCl → more successful collisions per second → faster rate.
Answer
Powder has much larger surface area than chips; more CaCO₃ particles are exposed to HCl; more frequent collisions; faster rate.
Question
Describe an experiment to investigate the effect of temperature on the rate of reaction between sodium thiosulfate solution and hydrochloric acid.
Step-by-step solution
Step 1
Place a conical flask on a piece of paper marked with a cross. Add a fixed volume (e.g. 50 cm³) of sodium thiosulfate solution.
Step 2
Heat the thiosulfate solution to a chosen temperature (measure with thermometer). Add a fixed volume of HCl (e.g. 5 cm³) and start the stopwatch.
Step 3
Look down through the solution from above. Stop the timer when the cross is no longer visible (sulfur precipitate has formed).
Step 4
Repeat at different temperatures (e.g. 20, 30, 40, 50, 60 °C), keeping volume and concentration of both solutions constant.
Step 5
Calculate rate = 1/time for each temperature. Plot rate vs temperature.
Answer
Measure time for cross to disappear at different temperatures (fixed volume and concentration); rate = 1/time; plot rate vs temperature; rate increases with temperature.
Examiner tip
Control variables: same volumes, same concentrations, same cross, same observer. Rate = 1/t is a common Cambridge mark-scheme answer.
The formulae you need to memorise for rate (speed) of reaction on the Cambridge IGCSE 0654 paper, with every variable defined in plain English and a note on when to use it.
rate=time takenchange in quantity
When to use
Calculating the mean rate from experimental data.
Example
60 cm³ gas in 30 s → rate = 2 cm³/s
Definitions to memorise and the exact keywords mark schemes credit for rate (speed) of reaction answers — sharpened from recent examiner reports for the 2026 0654 sitting.
The change in amount of a reactant or product per unit time; can be measured as change in volume of gas (cm³/s), change in mass (g/s), or change in concentration (mol/dm³/s).
A model that states that chemical reactions occur only when particles collide with sufficient energy (at least equal to the activation energy) and with the correct orientation.
The minimum energy that colliding particles must have for a reaction to occur. Only collisions with energy ≥ activation energy are successful.
A collision between particles that results in a chemical reaction; requires energy ≥ activation energy and correct orientation.
The total area of solid material exposed to a reactant. Increasing surface area (e.g. by powdering) increases the rate of reaction by exposing more particles.
The traps other students keep falling into on rate (speed) of reaction questions — taken from recent Cambridge IGCSE 0654 examiner reports and mark schemes — and how to avoid them.
0654 Examiner Report 2023
Why it happens
Students know temperature increases collision frequency but forget the second, more significant effect on collision energy.
How to avoid it
Higher temperature → (1) more frequent collisions AND (2) more particles have energy ≥ activation energy. Both effects must be stated for full marks.
Why it happens
Students think catalysts participate and therefore must be depleted.
How to avoid it
Catalysts lower activation energy but are regenerated at the end of the reaction; their mass and chemical composition are unchanged.
Why it happens
Students write 'more concentrated' when describing why a smaller particle size increases rate.
How to avoid it
Surface area (solid reactant) and concentration (dissolved/gas reactant) are different factors. Use 'surface area' for solids; 'concentration' for solutions/gases.
The things students keep getting wrong in this sub-topic, answered.