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Detailed notes on Acids, Bases and Salts for Cambridge IGCSE Coordinated Science, covering key concepts, explanations, examples, and exam-focused revision points.
The method used to prepare a salt depends on whether it is soluble or insoluble. Cambridge tests four preparation methods: titration (soluble from strong acid + alkali), excess solid method (soluble from acid + metal/carbonate/oxide), and precipitation (insoluble).
Mapped to the Cambridge IGCSE 0654 syllabus (2025-2027).
Two methods for soluble salts: titration (acid + alkali) or excess solid (acid + metal/oxide/carbonate). Both end with filtration and crystallisation.
Method 1 — Titration (acid + alkali): Used when BOTH reactants are soluble (and the salt is also soluble).
Why no indicator in the repeat? The indicator itself is a coloured organic compound that would contaminate the pure salt crystals.
Method 2 — Excess solid method (acid + insoluble metal/oxide/carbonate): Used when reactant is an insoluble solid (metal, metal oxide, metal carbonate).
Example: Copper(II) sulfate: CuO + H₂SO₄ → CuSO₄ + H₂O → blue crystals (CuSO₄·5H₂O) after crystallisation
Insoluble salts are made by mixing two solutions whose ions form an insoluble product. The precipitate is filtered, washed, and dried.
Precipitation method — for insoluble salts:
Example — Barium sulfate (BaSO₄):
BaCl₂(aq) + Na₂SO₄(aq) → BaSO₄(s) + 2NaCl(aq) Ionic equation: Ba²⁺(aq) + SO₄²⁻(aq) → BaSO₄(s)
Example — Silver chloride (AgCl):
AgNO₃(aq) + NaCl(aq) → AgCl(s) + NaNO₃(aq) Ionic equation: Ag⁺(aq) + Cl⁻(aq) → AgCl(s)
Solubility rules (for predicting precipitates):
| Ion | Solubility rule |
|---|---|
| NO₃⁻ (nitrate) | All soluble |
| Cl⁻ (chloride) | All soluble EXCEPT AgCl, PbCl₂ |
| SO₄²⁻ (sulfate) | All soluble EXCEPT BaSO₄, PbSO₄, CaSO₄ (sparingly) |
| CO₃²⁻ (carbonate) | Insoluble EXCEPT Na₂CO₃, K₂CO₃, (NH₄)₂CO₃ |
| OH⁻ (hydroxide) | Insoluble EXCEPT NaOH, KOH, Ca(OH)₂ (sparingly) |
Verbatim phrases and definitions Cambridge mark schemes credit.
Paper 4: 'Describe how to prepare pure crystals of copper(II) sulfate from copper(II) oxide and dilute sulfuric acid' (5 marks — excess solid, warming, filter, evaporate, crystallise, filter, dry). 'Write the ionic equation for the formation of barium sulfate precipitate' (2 marks — Ba²⁺ + SO₄²⁻ → BaSO₄ with state symbols). 'Identify which of these pairs of solutions would form a precipitate when mixed, and name the precipitate' — tests solubility rules.
Sources: Cambridge IGCSE Coordinated Sciences 0654 syllabus 2025-2027 (C8); 0654 Examiner Reports 2022-2024. Last reviewed 2026-05-14.
Step-by-step solutions to past-paper-style questions on preparation of salts, written exactly the way a tutor would explain them at the board.
Question
Describe how to prepare a pure, dry sample of copper(II) sulfate crystals from copper(II) oxide and dilute sulfuric acid.
Step-by-step solution
Step 1
Add excess copper(II) oxide (black powder) to warm dilute sulfuric acid in a beaker. Stir/warm gently.
CuO+H2SO4→CuSO4+H2O
Step 2
Continue adding CuO until no more dissolves (excess ensures all acid is used up). The solution turns blue.
Step 3
Filter the mixture to remove excess unreacted CuO (residue on filter paper); the blue filtrate is copper sulfate solution.
Step 4
Evaporate the filtrate gently until saturated (test: a glass rod dipped in the solution forms crystals on cooling). Allow to cool to form blue crystals.
Step 5
Filter off the crystals and dry them between filter paper (or in a warm oven at low temperature).
Answer
Add excess CuO to warm H₂SO₄; filter off excess CuO; evaporate filtrate to saturation; cool to crystallise; filter; dry.
Examiner tip
Must use excess CuO to ensure all acid is used (otherwise the salt would be contaminated with acid). Do not boil to dryness.
Question
Describe how to prepare a pure sample of lead(II) sulfate (an insoluble salt).
Step-by-step solution
Step 1
Prepare a solution of lead(II) nitrate (Pb(NO₃)₂) and a solution containing sulfate ions (e.g. dilute sulfuric acid or sodium sulfate solution).
Step 2
Mix the two solutions together in a beaker. A white precipitate of lead(II) sulfate immediately forms.
Pb2+(aq)+SO42−(aq)→PbSO4(s)
Step 3
Filter the mixture; the white precipitate (PbSO₄) is collected on the filter paper.
Step 4
Wash the precipitate with distilled water to remove any soluble impurities (e.g. remaining Pb²⁺ or SO₄²⁻ ions).
Step 5
Dry the precipitate in a warm oven or leave in air.
Answer
Mix Pb(NO₃)₂ solution with H₂SO₄ or Na₂SO₄ solution; white PbSO₄ precipitate forms; filter; wash with distilled water; dry.
Question
State why copper metal cannot be reacted directly with dilute hydrochloric acid to prepare copper(II) chloride.
Step-by-step solution
Step 1
Copper is below hydrogen in the metal reactivity series.
Step 2
Metals below hydrogen in the reactivity series do not react with dilute acids; they cannot displace hydrogen from acid.
Step 3
Instead, copper(II) oxide or copper(II) carbonate can be used: CuO + 2HCl → CuCl₂ + H₂O.
Answer
Copper is below hydrogen in the reactivity series and does not react with dilute HCl; use copper oxide or copper carbonate + HCl instead.
Examiner tip
Never use copper metal + acid. This is a classic exam trap for 'preparing copper salts'.
Question
Write the ionic equation for the neutralisation reaction between hydrochloric acid and sodium hydroxide solution.
Step-by-step solution
Step 1
Full equation: HCl(aq) + NaOH(aq) → NaCl(aq) + H₂O(l)
Step 2
All aqueous species are split into ions: H⁺ + Cl⁻ + Na⁺ + OH⁻ → Na⁺ + Cl⁻ + H₂O
Step 3
Cancel spectator ions (Na⁺ and Cl⁻ appear on both sides).
H+(aq)+OH−(aq)→H2O(l)
Answer
H+(aq)+OH−(aq)→H2O(l)
Definitions to memorise and the exact keywords mark schemes credit for preparation of salts answers — sharpened from recent examiner reports for the 2026 0654 sitting.
An ionic compound formed when the hydrogen in an acid is replaced by a metal (or ammonium) ion; produced by the reaction of an acid with a base, carbonate, or reactive metal.
The formation of an insoluble product (precipitate) when two solutions are mixed; used to prepare insoluble salts.
A reactant added in greater than the stoichiometric amount to ensure complete reaction of the other reactant. The excess is removed by filtration after the reaction.
A salt that dissolves significantly in water (>1 g per 100 g water); prepared by acid + reactive metal, acid + insoluble base, or acid + carbonate, then crystallisation.
A salt that does not dissolve significantly in water; prepared by mixing two solutions of soluble ionic compounds (precipitation).
The traps other students keep falling into on preparation of salts questions — taken from recent Cambridge IGCSE 0654 examiner reports and mark schemes — and how to avoid them.
0654 Examiner Report 2023
Why it happens
Students add a calculated amount of base, leaving some acid unreacted in the filtrate.
How to avoid it
Always add excess of the insoluble base (e.g. CuO) to ensure all the acid reacts; then filter off the unreacted base.
Why it happens
Students apply the 'metal + acid → salt + hydrogen' rule without checking reactivity.
How to avoid it
This reaction does not occur because Cu is below H in the reactivity series. Use CuO + 2HCl → CuCl₂ + H₂O instead.
Why it happens
Students filter and dry without removing soluble impurities trapped on the precipitate.
How to avoid it
Always wash the precipitate on the filter paper with distilled water to remove any ions from the mother liquor before drying.
The things students keep getting wrong in this sub-topic, answered.