What is a polygon in the context of Edexcel IGCSE Mathematics?

In Edexcel IGCSE Mathematics, a polygon is defined as a two-dimensional geometric figure with straight sides. Polygons are closed shapes with a minimum of three sides, such as triangles, quadrilaterals, and pentagons. Understanding polygons is essential for solving problems in Geometry and Trigonometry.

How do you calculate the sum of interior angles of a polygon?

To calculate the sum of the interior angles of a polygon, you can use the formula (n - 2) × 180°, where 'n' is the number of sides in the polygon. This formula is crucial for solving various problems in the Edexcel IGCSE Geometry and Trigonometry syllabus.

What distinguishes a regular polygon from an irregular polygon?

A regular polygon has all sides and angles equal, such as an equilateral triangle or a square. In contrast, an irregular polygon has sides and angles of different lengths and measures. Recognizing these differences is important for understanding properties and solving problems in Edexcel IGCSE Mathematics.

How can you determine the exterior angle of a regular polygon?

The exterior angle of a regular polygon can be determined using the formula 360°/n, where 'n' is the number of sides. This concept is frequently tested in the Edexcel IGCSE Geometry and Trigonometry curriculum, as it helps in understanding the properties of polygons.

What are some real-life applications of polygons studied in Edexcel IGCSE Mathematics?

Polygons are used in various real-life applications such as architecture, engineering, and computer graphics. Understanding the properties of polygons helps in designing structures, creating computer models, and solving practical problems, making it a vital part of the Edexcel IGCSE Mathematics curriculum.

Why is "Using $n \times 180$ instead of $(n-2) \times 180$" a common mistake in Polygons?

Why it happens: Forgetting the -2. How to avoid it: Remember: a triangle (n = 3) has 180°, not 540°. So (n-2) × 180.

Why is "Forgetting to divide by $n$ for regular polygons" a common mistake in Polygons?

Why it happens: Stopping after sum. How to avoid it: Sum tells you the TOTAL of all angles. To find ONE, divide by n. Source: 4MA1/1H Jan 2024 — examiner report Q6

Why is "Applying regular polygon formula to irregular" a common mistake in Polygons?

Why it happens: Not reading carefully. How to avoid it: Only REGULAR polygons have all angles equal. Irregular: just use sum formula and the given angles.

Geometry and TrigonometryEdexcel IGCSE Mathematics (4MA1)

Polygons

Work through the notes, try the practice questions, then take the quiz. The report tells you exactly what to revise next.

Previous Next

Learn this Topic

Start with the slides for the quick version, then go deeper with the full study notes.

Short Study Notes in the form of Slides

Read the notes first. If the method in a worked example clicks, you're ready for the questions.

Page 1 / 0

Detailed Study Notes

Full prose, callouts and a recap — built for A* mastery, not just a quick scan.

Take these study notes with you

Download a branded PDF — full prose, callouts, recap and memorise list for Polygons, ready to print or save offline.

Polygons Study Notes — Edexcel IGCSE 4MA1 Higher Tier (2026 onwards)

Interior and exterior angles of regular and irregular polygons. Two key formulae.

What you’ll learn

Mapped to the Cambridge IGCSE 4MA1 syllabus (2026 onwards).

4.2 — Use the formula for the sum of interior angles.
4.2 — Find each angle of a regular polygon.
4.2 — Use exterior angle properties.
4.2 — Find the number of sides given an angle.

The two key formulae

Interior sum = $(n-2) \times 180°$ . Exterior sum always $360°$ .

Sum of interior angles: $(n - 2) \times 180°$ .

Polygon	$n$	Sum of interior
Triangle	3	$180°$
Quadrilateral	4	$360°$
Pentagon	5	$540°$
Hexagon	6	$720°$
Heptagon	7	$900°$
Octagon	8	$1080°$
Nonagon	9	$1260°$
Decagon	10	$1440°$

Why $(n - 2) \times 180°$ ? Any $n$ -gon can be split into $n - 2$ TRIANGLES from one vertex. Each triangle has $180°$ . Total: $(n-2) \times 180°$ .

Sum of exterior angles: ALWAYS $360°$ , regardless of $n$ .

Why? Walk around the polygon: at each vertex, you turn through the exterior angle. After going all the way round, you've turned through a complete $360°$ . So all exterior angles sum to $360°$ .

For REGULAR polygons (all angles equal):

Each interior	$\dfrac{(n - 2) \times 180°}{n}$
Each exterior	$\dfrac{360°}{n}$

Examples:

Regular polygon	$n$	Each interior	Each exterior
Triangle	3	$60°$	$120°$
Square	4	$90°$	$90°$
Pentagon	5	$108°$	$72°$
Hexagon	6	$120°$	$60°$
Octagon	8	$135°$	$45°$
12-gon	12	$150°$	$30°$

Edexcel tip. Use the EXTERIOR angle method for finding $n$ — easier algebraically.

Interior sum: $(n - 2) \times 180°$ .
Exterior sum: $360°$ always.
Regular: divide sum by $n$ .
Each ext (regular) = $360/n$ .

Applications: finding $n$ or unknown angles

Use the formulae. Set up equations. Solve.

Find the number of sides given the interior angle.

Method 1 (using interior):

Each interior angle = $\dfrac{(n-2) \times 180}{n}$ .
Set equal to given value, solve for $n$ .

Method 2 (easier — using exterior):

Each exterior = $180 -$ interior.
$n = 360/$ exterior.

Example. Regular polygon with interior angle $156°$ . Find $n$ .

Exterior = $180 - 156 = 24°$ .
$n = 360 / 24 = 15$ sides.

Find missing angle in IRREGULAR polygon.

Use the SUM formula:

Sum of interior = $(n-2) \times 180°$ .
Add given angles, subtract from sum to find missing.

Example. Pentagon with angles $100°, 110°, 95°, 130°$ , and $x$ . Find $x$ .

Sum: $(5-2) \times 180 = 540°$ .
$x = 540 - 100 - 110 - 95 - 130 = 105°$ .

Worked qualitative. Why is the exterior method faster for finding $n$ ?

Avoid solving $\dfrac{(n-2) \cdot 180}{n} =$ angle (needs algebra).
Just compute exterior, then $n = 360/$ exterior.
Single division vs solving equation.

Edexcel tip. Show the formula explicitly, then substitute. Mark schemes credit each step.

Find $n$ via exterior: $n = 360/$ ext.
Irregular: sum formula, subtract.
Show formula, then substitute.
Always check answer makes sense.

How it’s examined

Polygons every Higher Tier paper (4-6 marks). Standard format: regular polygon, find each angle / number of sides. Examiner reports flag (1) using $n \times 180$ instead of $(n-2)$ , (2) forgetting to divide by $n$ for regular.

Sources: Pearson Edexcel International GCSE Mathematics A 4MA1 specification (2026 onwards); 4MA1 Examiner Reports — Jan and May/Jun 2022-2024 series; Past Papers — 4MA1/1H Jan 2024. Last reviewed 2026-05-07.

Master this Topic

Worked examples, formulae, definitions and the mistakes examiners flag — everything you need to push from a pass to an A*.

Take this whole topic with you

Download a branded revision sheet — worked examples, formulae, definitions and common mistakes for Polygons, ready to print or save as PDF.

Step-by-step worked examples — Polygons

Step-by-step solutions to past-paper-style questions on polygons, written exactly the way a tutor would explain them at the board.

1Sum of interior angles
Foundation• interior, polygon
Question
Find the sum of interior angles of a hexagon (6 sides).
Step-by-step solution
1. Step 1
  Sum of interior angles = $(n - 2) \times 180°$ .
2. Step 2
  $n = 6$ : $(6 - 2) \times 180 = 4 \times 180 = 720°$ .
Answer
$720°$
2Interior angle of a regular polygon
Foundation• Adapted from 4MA1/1H Jan 2024 Q6• regular polygon
Question
Find the size of each interior angle of a regular octagon.
Step-by-step solution
1. Step 1
  Sum: $(8 - 2) \times 180 = 1080°$ .
2. Step 2
  Regular: divide equally by $8$ : $1080 / 8 = 135°$ .
Answer
$135°$
Examiner tip
For regular polygon: SUM divided by NUMBER OF SIDES. State both steps.
3Find number of sides from interior angle
Higher• polygon, find sides
Question
A regular polygon has interior angles of $156°$ . How many sides does it have?
Step-by-step solution
1. Step 1
  Exterior angle = $180 - 156 = 24°$ .
2. Step 2
  Number of sides $= 360 / 24 = 15$ .
Answer
$15$ sides
Examiner tip
Easier route: exterior angle, then $n = 360/$ exterior. Edexcel mark schemes credit either method.
4Find missing angle in irregular polygon
Higher• irregular polygon
Question
A pentagon has angles $100°, 110°, 95°, 130°$ , and $x$ . Find $x$ .
Step-by-step solution
1. Step 1
  Sum of interior angles of pentagon: $(5 - 2) \times 180 = 540°$ .
2. Step 2
  $x = 540 - 100 - 110 - 95 - 130 = 105°$ .
Answer
$x = 105°$

Key Formulae — Polygons

The formulae you need to memorise for polygons on the Pearson Edexcel IGCSE 4MA1 paper, with every variable defined in plain English and a note on when to use it.

Sum of interior angles
$S = (n - 2) \times 180°$
$n$
number of sides
When to use
For ANY polygon (regular or irregular).
Example
Hexagon ( $n = 6$ ): $S = 720°$ .
Each interior angle of a regular polygon
$\dfrac{(n - 2) \times 180°}{n}$
$n$
number of sides
When to use
For regular polygons only.
Example
Regular pentagon: $(5-2) \cdot 180 / 5 = 108°$ .
Sum of exterior angles
$\text{Sum} = 360°\ \text{for any polygon}$
When to use
Always — sum of exterior angles is fixed for any polygon.
Example
Regular pentagon: each exterior $= 360/5 = 72°$ .

Key Definitions and Keywords — Polygons

Definitions to memorise and the exact keywords mark schemes credit for polygons answers — sharpened from recent examiner reports for the 2026 Pearson Edexcel IGCSE 4MA1 sitting.

Polygon
Examiner keyword
A 2D shape with straight sides. $n$ sides → $n$ -gon.
Example
Triangle (3), quadrilateral (4), pentagon (5), hexagon (6), octagon (8).
Regular polygon
Examiner keyword
A polygon with all sides equal AND all angles equal.
Example
Equilateral triangle. Square. Regular hexagon.
Interior angle
Examiner keyword
An angle inside the polygon, between two adjacent sides.
Exterior angle
The supplement of the interior angle. $180°$ minus interior.

Common Mistakes and Misconceptions — Polygons

The traps other students keep falling into on polygons questions — taken from recent Pearson Edexcel IGCSE 4MA1 examiner reports and mark schemes — and how to avoid them.

✕Using $n \times 180$ instead of $(n-2) \times 180$
Why it happens
Forgetting the $-2$ .
How to avoid it
Remember: a triangle ( $n = 3$ ) has $180°$ , not $540°$ . So $(n-2) \times 180$ .
✕Forgetting to divide by $n$ for regular polygons
4MA1/1H Jan 2024 — examiner report Q6
Why it happens
Stopping after sum.
How to avoid it
Sum tells you the TOTAL of all angles. To find ONE, divide by $n$ .
✕Applying regular polygon formula to irregular
Why it happens
Not reading carefully.
How to avoid it
Only REGULAR polygons have all angles equal. Irregular: just use sum formula and the given angles.

Practice questions

Exam-style questions with step-by-step worked solutions. Try one before checking the method.

Past paper style quiz

Get a report showing which sub-topics you've nailed and which ones still need work.

Video lesson

Short walkthrough of the concepts students most often get stuck on.

Polygons — frequently asked questions

The things students keep getting wrong in this sub-topic, answered.

Polygon

n

Sum of interior

Triangle

180°

Quadrilateral

360°

Pentagon

540°

Hexagon

720°

Heptagon

900°

Octagon

1080°

Nonagon

1260°

Decagon

1440°

Each interior

\dfrac{(n - 2) \times 180°}{n}

Each exterior

\dfrac{360°}{n}

Regular polygon

n

Each interior

Each exterior

Triangle

60°

120°

Square

90°

90°

Pentagon

108°

72°

Hexagon

120°

60°

Octagon

135°

45°

12-gon

150°

30°

Find the number of sides given the interior angle.

Method 1 (using interior):

Each interior angle = $\dfrac{(n-2) \times 180}{n}$ .
Set equal to given value, solve for $n$ .

Method 2 (easier — using exterior):

Each exterior = $180 -$ interior.
$n = 360/$ exterior.

Example. Regular polygon with interior angle $156°$ . Find $n$ .

Exterior = $180 - 156 = 24°$ .
$n = 360 / 24 = 15$ sides.

Find missing angle in IRREGULAR polygon.

Use the SUM formula:

Sum of interior = $(n-2) \times 180°$ .
Add given angles, subtract from sum to find missing.

Example. Pentagon with angles $100°, 110°, 95°, 130°$ , and $x$ . Find $x$ .

Sum: $(5-2) \times 180 = 540°$ .
$x = 540 - 100 - 110 - 95 - 130 = 105°$ .

Worked qualitative. Why is the exterior method faster for finding $n$ ?

Avoid solving $\dfrac{(n-2) \cdot 180}{n} =$ angle (needs algebra).
Just compute exterior, then $n = 360/$ exterior.
Single division vs solving equation.

Edexcel tip. Show the formula explicitly, then substitute. Mark schemes credit each step.

Polygons

Short Study Notes in the form of Slides

Detailed Study Notes

What you’ll learn

How it’s examined

1Sum of interior angles

2Interior angle of a regular polygon

3Find number of sides from interior angle

4Find missing angle in irregular polygon

Sum of interior angles

Each interior angle of a regular polygon

Sum of exterior angles

Polygon

Regular polygon

Interior angle

Exterior angle

✕Using n×180n \times 180n×180 instead of (n−2)×180(n-2) \times 180(n−2)×180

✕Forgetting to divide by nnn for regular polygons

✕Applying regular polygon formula to irregular

Practice questions

Past paper style quiz

Assess your understanding

Video lesson

Polygons — frequently asked questions

Polygons

Short Study Notes in the form of Slides

Detailed Study Notes

What you’ll learn

How it’s examined

1Sum of interior angles

2Interior angle of a regular polygon

3Find number of sides from interior angle

4Find missing angle in irregular polygon

Sum of interior angles

Each interior angle of a regular polygon

Sum of exterior angles

Polygon

Regular polygon

Interior angle

Exterior angle

✕Using n×180n \times 180n×180 instead of (n−2)×180(n-2) \times 180(n−2)×180

✕Forgetting to divide by nnn for regular polygons

✕Applying regular polygon formula to irregular

Practice questions

Past paper style quiz

Assess your understanding

Video lesson

Polygons — frequently asked questions

✕Using $n \times 180$ instead of $(n-2) \times 180$

✕Forgetting to divide by $n$ for regular polygons

✕Using $n \times 180$ instead of $(n-2) \times 180$

✕Forgetting to divide by $n$ for regular polygons